Answer:
Let the speed of the train be x km/h.
Case 1:
Distance = 288 km
Speed = x km/h
Time = Distance/Speed
= 288/x h
Case 2:
Distance = 288 km
Speed = (x+4) km/h
Time = 288/x + 4 h
Since 288/x > 288/x + 4
288/x - 288/x+4 = 1
288[1/x - 1/x+4 ] = 1
[ x + 4 - x / x(x + 4) ] = 1/288
[4 / x^2 + 4x ] = 1/288
x^2 + 4x = 1152
x^2 + 4x - 1152 = 0
x^2 + 36x - 32x - 1152 = 0
x(x + 36) - 32(x + 36) = 0
(x + 36)(x - 32) = 0
x + 36 = 0 , x - 32 = 0
x = -36 , x = 32
x = -36 , rejected since speed cannot be negative.
Therefore , speed of the train = 32 km/h
Answer: 19 days
Step-by-step explanation:
305-115=190
190 divided by 10= 19
So the right answer is 9g^20p^16
look at the attached picture
Hope it will help you
Good luck on your assignment
Recall that parallel lines have the same slope.
A line parallel to y= (-3/5)x + 8 would have the same equation EXCEPT for a different constant, C, replacing that '8.'
This new line passes thru (-5,-3). In y= (-3/5)x + C, replace x with -5 and replace y with -3. Then:
-3 = (-3/5)(-5) + C. Find C:
-3 = 3 + C. Thus, C = 6
Thus, the equation of the new line is y= -(3/5)x - 6
Check: Let x = -5 and y = -3. Is the above equation true?
-3 = (-3/5)(-5) - 6
-3 = 3 - 6, or -3 = -3.
