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ioda
3 years ago
5

During winter, Detroit is colder than Boston but warmer than Minneapolis. Which inequality correctly compares the winter tempera

tures of the three cities?
1. Detroit temperature's < Boston's temperature < Minneapolis's temperature
2. Minneapolis's temperature < Detroit's temperature < Boston's temperature
3. Boston's temperature < Minneapolis's temperature < Detroit's temperature
4. Detroit's temperature < Minneapolis's temperature < Boston's temperature
Mathematics
2 answers:
Nat2105 [25]3 years ago
5 0
We will take one given at a time, the common place is "Detroit", so we will take it as a reference.

1- Detroit is colder than Boston, this means that:
Temperature in Detroit < Temperature in Boston .........> I

2- Detroit is warmer that <span>Minneapolis, this means that:
Temperature is </span><span>Minneapolis < Temperature in Detroit .........> II

From I and II, we can conclude that:
</span><span>Minneapolis has the lowest temperature, followed by Detroit and then Boston.

Comparing this to the choices, we will find that the correct choice is:
</span><span>2. Minneapolis's temperature < Detroit's temperature < Boston's temperature</span>
Otrada [13]3 years ago
3 0

Answer:

2. Minneapolis's temp<Detroit's temp<Boston's temp.

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Step-by-step explanation:

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Make y the subject

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Replace y with a'(d)

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Prove that a(d) and a'(d) are inverse functions

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To do this, we prove that:

a(a'(d)) = a'(a(d)) = d

Solving for a(a'(d))

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a(a'(d))  = \frac{5d}{5} + \frac{15}{5} - 3

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Solving for: a'(a(d))

a'(a(d)) = a'(5d - 3)

Substitute 5d - 3 for d in a'(d) = \frac{d}{5} + \frac{3}{5}

a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}

Add fractions

a'(a(d)) = \frac{5d - 3+3}{5}

a'(a(d)) = \frac{5d}{5}

a'(a(d)) = d

Hence:

a(a'(d)) = a'(a(d)) = d

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