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ioda
3 years ago
5

During winter, Detroit is colder than Boston but warmer than Minneapolis. Which inequality correctly compares the winter tempera

tures of the three cities?
1. Detroit temperature's < Boston's temperature < Minneapolis's temperature
2. Minneapolis's temperature < Detroit's temperature < Boston's temperature
3. Boston's temperature < Minneapolis's temperature < Detroit's temperature
4. Detroit's temperature < Minneapolis's temperature < Boston's temperature
Mathematics
2 answers:
Nat2105 [25]3 years ago
5 0
We will take one given at a time, the common place is "Detroit", so we will take it as a reference.

1- Detroit is colder than Boston, this means that:
Temperature in Detroit < Temperature in Boston .........> I

2- Detroit is warmer that <span>Minneapolis, this means that:
Temperature is </span><span>Minneapolis < Temperature in Detroit .........> II

From I and II, we can conclude that:
</span><span>Minneapolis has the lowest temperature, followed by Detroit and then Boston.

Comparing this to the choices, we will find that the correct choice is:
</span><span>2. Minneapolis's temperature < Detroit's temperature < Boston's temperature</span>
Otrada [13]3 years ago
3 0

Answer:

2. Minneapolis's temp<Detroit's temp<Boston's temp.

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Step-by-step explanation:

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The owners of an eyeglass store claim that they fill customers' orders, on average, in 60 minutes with a standard deviation of 1
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By applying z-score formula we got that if a reporter determines a mean order time of 63 minutes then value o Z is 1.19

<h3>What is standard deviation?</h3>

Standard deviation is a number used to tell how measurements for a group are spread out from the average (mean), or expected value

Here given that

The owners of an eyeglass store claim that they fill customers' orders, on average, in 60 minutes with a standard deviation of 15. 9 minutes. Based on a random sample of 40 orders, a reporter determines a mean order time of 63 minutes

mean=μ=60

standard deviation=σ=15.9

number of sample=n=40

\bar{x}=63 \\

Now we can calculate z by z-score formula as

z=\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}}}  \\\\&=\frac{63-60}{\frac{15 \cdot 9}{40}} \\ \\=\frac{3}{2.5140} \\ \\=1.19\end{aligned}

By applying z-score formula we got that if a reporter determines a mean order time of 63 minutes then value o Z is 1.19

To learn more about standard deviation visit :brainly.com/question/12402189

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