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My name is Ann [436]
4 years ago
15

Select all of the following equation(s) that are quadratic in form.

Mathematics
1 answer:
charle [14.2K]4 years ago
5 0

Answer:

A, D, E

Step-by-step explanation:

on edg... Good Luck!!

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Solve the inequality. Graph the solution
Anna35 [415]
Here are the first 3 to show you how to do them

4 0
3 years ago
Car travels 100 m in 5 seconds. What is the speed the car?
weqwewe [10]
How you do this is using the formula speed = distance/time. So this is 100/5 which is 20 meters a second. Using the conversion factor (can google "20 meters per second is how many mile") 20 meters a second = 44.7 miles per hour.

In conclusion, the answer you're looking for is D. 44.7 miles per hour.
4 0
3 years ago
Read 2 more answers
If quadrilateral MNPO is reflected over the x-axis, what are the coordinates of
jenyasd209 [6]

<em>Note: you have not added the image, so I am assuming the quadrilateral MNOP with coordinates M(-4, 0), N(5, -3), P(2, 6) and O(-5, 7). It will anyhow clear your concept as I would explain the concept of reflection over the x-axis.</em>

Step-by-step explanation:

Considering the quadrilateral MNPO with assumed vertices

  • <em>M(-4, 0)</em>
  • <em>N(5, -3)</em>
  • <em>P(2, 6)</em>
  • <em>O(-5, 7)</em>

<em />

<em>THE RULE OF REFLECTION </em>states that when we tend to reflect a point let say (x, y), across the x-axis, the x-coordinate does not change or transform, but the y-coordinate is changed into its opposite sign i.e. (x,-y).

So, the coordinates of the point in the image after quadrilateral MNPO is reflected over the x-axis will be:

<h3>(x, y)                      (x, -y)</h3>

<em>M(-4, 0)                     M'(-4, 0)</em>

<em>N(5, -3)                     N'(5, 3)</em>

<em>P(2, 6)                      P'(2, -6)</em>

<em>O(-5, 7)                   O'(-5, -7)</em>

Hope, it will help you clear your concept regarding reflection of an object over the x-axis. Using this understanding, you can solve any other question related to this topic.

6 0
4 years ago
Approximate the change in the volume of a sphere when its radius changes from r = 30 ft to r=10.1 ft [v(r)=4/3Ï€r^3]. When r cha
ella [17]

Answer: ∆V for r = 10.1 to 10ft

∆V = 40πft^3 = 125.7ft^3

Approximate the change in the volume of a sphere When r changes from 10 ft to 10.1 ft, ΔV=_________

[v(r)=4/3Ï€r^3].

Step-by-step explanation:

Volume of a sphere is given by;

V = 4/3πr^3

Where r is the radius.

Change in Volume with respect to change in radius of a sphere is given by;

dV/dr = 4πr^2

V'(r) = 4πr^2

V'(10) = 400π

V'(10.1) - V'(10) ~= 0.1(400π) = 40π

Therefore change in Volume from r = 10 to 10.1 is

= 40πft^3

Of by direct substitution

∆V = 4/3π(R^3 - r^3)

Where R = 10.1ft and r = 10ft

∆V = 4/3π(10.1^3 - 10^3)

∆V = 40.4π ~= 40πft^3

And for R = 30ft to r = 10.1ft

∆V = 4/3π(30^3 - 10.1^3)

∆V = 34626.3πft^3

3 0
4 years ago
Help pleaseeeeeeeeee
Korolek [52]

Answer:

2x+2x is 4 +3x is 12+ 1 is 13 + 3 is 15 - 2 is 13 -1 is 12

so x=15

and y=12

7 0
3 years ago
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