Ask question

Ask question

All categories

3 years ago

6

A farmer grows vegetables on a rectangular plot of land. The length of the plot is labeled in the diagram below. If the perimete

r of the plot is (6x2 + 46x + 68) meters, what is its width?

1 answer:

gavmur [86]3 years ago

4 0

Answer:

Step-by-step explanation:

solve the question then divide

You might be interested in

Need help horribly geometry question

Angelina_Jolie [31]

Answer:

23.31 ft

Step-by-step explanation:

Reference angle = 47°

Opp = 25 ft

Adj = x

Apply trigonometry ratio TOA:

Tan 47 = Opp/Adj

Tan 47 = 25/x

x*Tan 47 = 25

x = 25/Tan 47

x = 23.3128772 ≈ 23.31 ft (to 2 d.p)

7 0

3 years ago

-18 - 14= whats the answer help

AveGali [126]

Answer:

-32 :) is the answer just think about it as your adding the sum of these numbers then putting a negative in front of it.

Step-by-step explanation:

5 0

3 years ago

Use proper probability notation. Identify function and label inputs when using technology.

zhannawk [14.2K]

Answer:

0.1349

Step-by-step explanation:

Given that:

Sample size, n = 500

20% of 500 ; 0.2 * 500 = 100

p = 0.18 ; n = 500 ; 1 - p = 0.82

P(x ≥ 100) ;

Using the binomial probability relation :

P(x =x) = nCx * p(x)^x * (1 - p)^(n - x

P(x ≥ 100) = 500C100 * 0.18^100 * 0.82^400

P(x ≥ 100) = 0.1349

5 0

3 years ago

A bag contains 4 blue marbles and 2 yellow marbles. Two marbles are randomly chosen (the first marble is NOT replaced before dra

VMariaS [17]

Answer:

0.4 = 40% probability that both marbles are blue.

0.0667 = 6.67% probability that both marbles are yellow.

53.33% probability of one blue and then one yellow

If you are told that both selected marbles are the same color, 0.8571 = 85.71% probability that both are blue

Step-by-step explanation:

To solve this question, we need to understand conditional probability(for the final question) and the hypergeometric distribution(for the first three, because the balls are chosen without being replaced).

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

What is the probability that both marbles are blue?

4 + 2 = 6 total marbles, which means that $N = 6$

4 blue, which means that $k = 4$

Sample of 2, which means that $n = 2$

This is P(X = 2). So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 2) = h(2,6,2,4) = \frac{C_{4,2}*C_{2,0}}{C_{6,2}} = 0.4$

0.4 = 40% probability that both marbles are blue

What is the probability that both marbles are yellow?

4 + 2 = 6 total marbles, which means that $N = 6$

2 yellow, which means that $k = 2$

Sample of 2, which means that $n = 2$

This is P(X = 2). So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 2) = h(2,6,2,2) = \frac{C_{2,2}*C_{4,0}}{C_{6,2}} = 0.0667$

0.0667 = 6.67% probability that both marbles are yellow.

What is the probability of one blue and then one yellow?

Total is 100%.

Can be:

Both blue(40%)

Both yellow(6.67%)

One blue and one yellow(x%). So

40 + 6.67 + x = 100

x = 100 - 46.67

x = 53.33

53.33% probability of one blue and then one yellow.

If you are told that both selected marbles are the same color, what is the probability that both are blue?

Conditional probability.

Event A: Both same color

Event B: Both blue

Probability of both being same color:

Both blue(40%)

Both yellow(6.67%)

This means that $P(A) = 0.4 + 0.0667 = 0.4667$

Probability of both being the same color and blue:

40% probability that both are blue, which means that $P(A \cap B) = 0.4$

Desired probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.4}{0.4667} = 0.8571$

If you are told that both selected marbles are the same color, 0.8571 = 85.71% probability that both are blue

8 0

3 years ago

SOMEONE, PLEASE ANSWER THIS!

IrinaVladis [17]

Answer:

Step-by-step explanation:

Solution

Start with the product

The product is 7*x where x is a number but not specified.

Now add 6

Answer: 7x + 6

This cannot be simplified any more than what it is now.

8 0

2 years ago

Read 2 more answers