For a function to begin to qualify as differentiable, it would need to be continuous, and to that end you would require that 
is such that
Obviously, both limits are 0, so 
is indeed continuous at 
.
Now, for to be differentiable everywhere, its derivative 
must be continuous over its domain. So take the derivative, noting that we can't really say anything about the endpoints of the given intervals:
and at this time, we don't know what's going on at , so we omit that case. We want to be continuous, so we require that
from which it follows that 
.
Answer:
a=-3
Step-by-step explanation:
-11a=45-12
-11a=33
a= -33/11
a=-3
Multiply 5.5 times 2.1
answer is 11.55in
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Answer:
Option B , C , E are characteristics of the function .
Step-by-step explanation:
Given : function f(x)=2(x-4)^5.
To find : What are the characteristics of the function .
Solution : We have given that f(x)=2
.
By the End Point behavior : if the degree is even and leading coefficient is odd of polynomial of function then left end of graph goes down and right goes up.
Since , Option E is correct.
It has degree 5 therefore, function has 5 zeros and atmost 4 maximua or minimum.
Option C is also correct.
By transformation rule it is vertical stretch and shift to right (B )
Therefore, Option B , C , E are characteristics of the function .
