Given 3 and 1 over 10 times negative six times 5 over 12, determine the product.

1 answer:

6 0

$3\frac{1}{10} \times -6\cdot \cfrac{5}{12}\implies \cfrac{3\cdot 10+1}{10} \times \cfrac{-6\cdot 5}{12}\implies \cfrac{31}{10}\times \cfrac{-6}{12}\cdot 5\implies \cfrac{31}{10}\times \cfrac{-1}{2}\cdot 5 \\\\\\ \cfrac{31}{10}\times \cfrac{-5}{2}\implies \cfrac{31\cdot -5}{10\cdot 2}\implies \cfrac{-155}{20}\implies -7\frac{3}{4}$

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