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charle [14.2K]
2 years ago
11

The equation of a hyperbola is x^2-4y^2-2x-15=0. What is the width of the asymptote rectangle?

Mathematics
1 answer:
zhenek [66]2 years ago
3 0

Answer:  8

<u>Step-by-step explanation:</u>

x² - 2x  + ___ - 4y²  = 15 + ___

x² - 2x  + <u> 1 </u> - 4y²  = 15 + <u> 1 </u>

(x - 1)² - 4(y)² = 16

\frac{(x-1)^{2}} {16} - \frac{4(y - 0)^{2}}{16} = \frac{16}{16}

\frac{(x-1)^{2}} {16} - \frac{(y - 0)^{2}}{4} = 1

r_{x} = 4   r_{y} = 2

width of rectangle is 2(r_{x}) = 2(4) = 8

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the concentration of a drug in a patient's bloodstream t hours after the drug was administrated presented by the equation c(t) =
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The graph of the function has no asymptotes.

<h3>The table of values of c(t)</h3>

The function is given as:

c(t) = 5t - t² + 1

When t = 1, 2, 5, 10;

We have:

c(1) = 5(1) - 1² + 1 = 5

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So, the table of values is

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1         5

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See attachment for the graph of the function

<u>The domain</u>

From the question, we understand that t represents time.

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So, the domain is 0 ≤ t ≤ 5.2

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From the graph, the maximum of the graph is 7.25

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Given a best fit line of :

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