m
=
−
2
, (
3,
5
)
Find the value of b
using the formula for the equation of a line.
b
=
11
Now that the values of
m (slope) and b
(y-intercept) are known, substitute them into
y
=
m
x
+
b to find the equation of the line. y
=
−
2
x
+
11
Answer: See the full explanation.
Step-by-step explanation:
You can actually do this using various life scenario. Let me help you with this example.
Suppose that one person is called Mike and he needs to buy something, here is your scenario for Mike to get what he want:
Mike wants to buy a pair of shoes that worth 37$ for a soccer game next week. He only has 5$ in his wallet. In order to get the remaining money, he decides to work in a market for a day. If the market pay 8$ per hour, how many hours does Mike need to have enough money to buy the shoes?.
This is the real life scenario. The equation is as above, because you can call "x" the number of hours needed, so as you solve the equation, you'll realize that the number of hours needed is 4:
8x + 5 = 37
8x = 37 - 5
8x = 32
x = 32/8 = 4 hours needed.
Answer:
a^3b + 2a^2b^2 + ab^3
Step-by-step explanation:
(a+b)^2
= a^2 + 2ab + b^2
ab(a^2 + 2ab + b^2)
= a^3b + 2a^2b^2 + ab^3
You need to find the area of the hexagon, and the area of the triangle.
The formula for the area of a triangle is
I hope this helps you a little.
Answer:
y = -4x - 6
Step-by-step explanation:
The equation of a line in point-slope form.
is the equation of the line containing point (x1, y1) and having slope, m.
The given point of the perpendicular bisector is (-1, -2), so in this case, x1 = -1, and y1 = -2.
We need the slope of the perpendicular bisector. First we find the slope of the segment. We start at point (-5, -3). We go up 1 unit and 4 units to the right, and we are at another point on the segment. Since slope = rise/run, the slope of the segment is 1/4. The slopes of perpendicular lines are negative reciprocals, so the slope of the perpendicular bisector is the negative reciprocal of 1/4, so for the perpendicular bisector, m = -4.
Now we use the equation above and our values.
