All categories

3 years ago

Y''+y'/x-y/x^2=0 y(1)=1, y(R)=n

Mathematics

1 answer:

Firlakuza [10]3 years ago

6 0

Here mate just take a look
http://www.math.ucla.edu/~skalyanswamy/13S-32A-limit_sols.pdf

You might be interested in

Find T, N, and kappa for the plane curve Bold r left parenthesis t right parenthesis equalsleft parenthesis 7 Bold cos t plus

pickupchik [31]

Answer:

Step-by-step explanation:

r(t) = (7 cost + 7t sin t)i + (7 sin t - 7t cos t)j

$\frac{d \bar r t}{dt} =(7\frac{d}{dt}\cos t + 7\frac{d}{dt} (t \sin t)i+(7\frac{d}{dt} \sin t-7\frac{d}{dt} t \cos t)j$

$=(7(-\sin t)+7(1* \sin t+t \cos t))i+(7 \cost -7(1*\cos t - t \sin t))j\\\\=7((-\sin t+\sin t+t \cos t)i+(\cos t-\cos t+t \sin t)j)\\\\=7((t\cos t)i+(t\sin t)j)$

$\bar r'(t)=\frac{d \bar r t}{dt} =(7t\cos t)i+(7t\sin t)j---(1)\\\\11\bar r(t)=\sqrt{(7t\cos t)^2+(7t\sin t)^2}\\\\=\sqrt{49t^2(\cos^2t+\sin^2 t)} \\\\=7t$

$\bar T (t)=\frac{\bar r'(t)}{11\bar r(t)11} =\frac{(7t\cos t)i+(7t\sin t)j}{7t} \\\\\barT(t)=(\cos t)i+(\sin t)j$

$\bar T'(t)=\frac{d}{dt} (\cos t)i+\frac{d}{dt} (\sin t) j\\\\\bar T'(t)=(-\sin t)i+(\cos t)j---(2)\\\\11\bar T'(t)=\sqrt{(-\sin t)^2+(\cos t)^2} \\\\=\sqrt{\sin^2t+\cos^2t} \\\\=1$

$\bar N(t)=\bar T'(t)=\frac{(-\sin t)i+(\cos t)j}{(1)} \\\\ \large \boxed {\bar N(t)=(-\sin t)i+(\cos t)j}$

$K(t)=\frac{|\b\r T'(t)|}{\bar r (t)|} \\\\=\frac{|-\sin t i+\cos t j|}{|7t\cos t +7t \sin t j|}$

Using eq (1) and (2)

$K(t)=\frac{\sqrt{(-\sin t)^2+(\cos t)^2} }{\sqrt{(7t\cos t)^2+(7t\sin t)^2} }\\\\=\frac{\sqrt{\sin^2 t+\cos^2t} }{\sqrt{49t^2(\cos^2 t+\sin^2t)} }\\\\=\frac{\sqrt{1} }{\sqrt{49t^2\times 1} } \\\\ \large \boxed {K(t)=\frac{1}{7t} }$

7 0

3 years ago

Estimate how many 1/3 pound boxes can be filled from a 5 3/4 lb bag of rice

Gnesinka [82]

The answer is 17 1/4 .Hope this helped.

4 0

2 years ago

A 4-column table with 4 rows titled Population Data. Column 1 has entries 4, 5, 9, 15. Column 2 has entries 8, 2, 20, 1. Column

zheka24 [161]

Answer: Row 3

Row 2

6 and 10

Step-by-step explanation: C B A

5 0

1 year ago

A stack of 5 books welghs 9.5 pounds. If each book weighs the same amount, how much does each book weigh?

Dafna11 [192]

9.5/5 = 1.9 lbs each

6 0

3 years ago

Question 20 please thank hou

Mekhanik [1.2K]

$\dfrac{9mn-6m}{25-m^2}\div\dfrac{12mn}{5+m}=\dfrac{3m(3n-2)}{5^2-m^2}\cdot\dfrac{5+m}{3m\cdot4n}\\\\=\dfrac{3n-2}{(5-m)(5+m)}\cdot\dfrac{5+m}{4n}=\dfrac{3n-2}{4n(5-m)}\to\boxed{C.}$

8 0

3 years ago