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Solnce55 [7]
4 years ago
10

Y''+y'/x-y/x^2=0 y(1)=1, y(R)=n

Mathematics
1 answer:
Firlakuza [10]4 years ago
6 0
Here mate just take a look
http://www.math.ucla.edu/~skalyanswamy/13S-32A-limit_sols.pdf

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Plz answer the rest..... will mark as brainlist​
dedylja [7]

Answer:

I answered it using pictures because I dont know how else to put the answers down.

5 0
3 years ago
Point F is on line CD. Find the measure of angle CFE. Show your work.
wel

Answer:

CFD = 180

EFD= 152

180-152= 28

CFE= 28

Step-by-step explanation:

5 0
3 years ago
1. (9 + 5 ) + (13 +12÷)​
GenaCL600 [577]

Answer:

14+25=39

Step-by-step explanation:

9+5=14

13+12=25

7 0
4 years ago
The height, h, in feet of the tip of the hour hand of a wall clock varies from 9 feet to 10 feet. Which of the following equatio
AnnZ [28]

The motion of the hour hand of a clock is a periodic motion that repeats every 12 hours.

  • The equation that can be used to models the height as a function of time, based on the given options, is presented as follows; \displaystyle \underline{ H = 0.5 \cdot cos \left(\frac{\pi}{6} \cdot t \right) + 9.5}

Reasons:

The given parameters are;

The variation of the height of the tip of the hour hand = 9 feet to 10 feet

At t = 0, the time = 12.00 a.m.

Required: The equation that can be used to model the height as a function of time.

Solution:

The general form of the cosine function is presented as follows;

y = a·cos(b·x - c) + d

The amplitude = a

\displaystyle a  = \mathbf{ \frac{Maximum \ value -Minimum \ value}{2}}

Therefore;

\displaystyle a  = \frac{10 -9}{2} = 0.5

b = The cycle speed

The period, T, is given as follows;

\displaystyle T = \mathbf{ \frac{2 \cdot \pi}{b}}

The period of a block, T = 12 hours

Therefore;

\displaystyle b = \frac{2 \cdot \pi}{T}

\displaystyle b = \frac{2 \cdot \pi}{12} = \mathbf{ \frac{ \pi}{6}}

\displaystyle d  = \mathbf{ \frac{Maximum \ value +Minimum \ value}{2} = \frac{10 + 9 }{2}} = 9.5

At t = 0, H = The highest point = 10 ft.

Which gives;

\displaystyle H = \mathbf{0.5 \cdot cos \left(\frac{\pi}{6} \times 0  -c\right) + 9.5} = 10

\displaystyle  cos \left( -c\right)  = \frac{0.5}{0.5}  = 1

-c = arcos(1) = 0

-c = 0

c = 0

The equation is therefore;

\displaystyle H = \mathbf{0.5 \cdot cos \left(\frac{\pi}{6} \cdot t \right) + 9.5}

The above equation is the same as; <u>H = 0.5cosine (StartFraction pi Over 6 EndFraction t) + 9.5</u>

Learn more about the cosine function here:

brainly.com/question/4458343

brainly.com/question/24368105

4 0
3 years ago
Read 2 more answers
Describe how the graph is related to the graph of y = lxl.
Crazy boy [7]

Answer:

Vertical shift down 4 units

Step-by-step explanation:

Vertical shift down 4 units

8 0
4 years ago
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