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spayn [35]
2 years ago
10

Which expression is equivalent to 5 (2 + 7)?

Mathematics
2 answers:
SOVA2 [1]2 years ago
6 0
The answer wold be 5(2)+5(7)
Komok [63]2 years ago
4 0
So the answer would have to be because it the equivalent factor5(2)+5(7)
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Find the equation of the line with slope = -2 and passing through (3,2). Write your equation in the form
horrorfan [7]

Answer:

Step-by-step explanation:

y - 2 = -2(x - 3)

y - 2 = -2x + 6

y = -2x + 8

3 0
3 years ago
Find the following percentage of 4.2% of 50
aleksley [76]
4.2% of 50 is 2.1 So 2.1 is your answer
3 0
3 years ago
Write your question here (Keep it simple and clear to get the best answer)what is the domain of the function y=✓3-s?
Ilya [14]

Answer: D: s∈ (-∞, 3]

Step-by-step explanation:

When we have a function:

y = f(x)

The domain is the set of the possible values we can input in f(x).

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y = √(3 - s)

Where our variable is s.

So we want to find the possible values of s we can input in that function.

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Then the argument of the square root needs to be equal to or larger than zero.

This means that:

3 - s ≥ 0

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3 ≥ s

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6 0
2 years ago
A 2000-gallon metal tank to store hazardous materials was bought 15 years ago at cost of $100,000. What will a 5,000-gallon tank
harkovskaia [24]

Answer:

The value  is P_o = \$ 561958.9

Step-by-step explanation:

From the question we are told that

  The capacity of the metal  tank is  C =  2000 \  gallon

   The duration usage is  t = 15\ years \ ago

   The cost of 2000-gallon tank 15 years ago is P =  \$100,000

    The capacity of the second tank considered is C_1 = 5,000  

    The power sizing exponent is e = 0.57

     The initial construction cost index is  u_1 = 180

      The new construction after 15 years cost index is  u_2 =600

Equation for the power sizing exponent is mathematically represented as

      \frac{P_n}{P} = [\frac{C_1}{C} ]^{e}

=> Here P_n is the cost of 5,000-gallon tank as at 15 years ago  

So

     P_n  =  [\frac{5000}{2000} ] ^{0.57} * 100000

      P_n  =  \$168587.7

Equation for the cost index exponent is mathematically represented as

      \frac{P_o}{P_n}  =  \frac{u_2}{u_1}

HereP_o is the cost of 5,000-gallon tank today

So

       \frac{P_o}{168587.7}  =  \frac{600}{180}

=>    P_o = \frac{600}{180} * 168587.7

=>      P_o = \$ 561958.9

8 0
3 years ago
What is the answer ?
statuscvo [17]

Answer:

4

......................

6 0
3 years ago
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