Question:
A solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned his electric heat on, the excess be used up at 50 kilowatts hours per day
.
(a) If E represents the excess left and d represent the number of days. Write an equation for E in terms of d
(b) How much of excess will be left after one month (1 month = 30 days)
Answer:
a. 
b. 
Step-by-step explanation:
Given
Excess = 6500kwh
Rate = 50kwh/day
Solving (a): E in terms of d
The Excess left (E) in d days is calculated using:

The expression uses minus because there's a reduction in the excess kwh on a daily basis.
Substitute values for Excess, Rate and days


Solving (b); The value of E when d = 30.
Substitute 30 for d in 



<em>Hence, there are 5000kwh left after 30 days</em>
It refers to the number of times a number is being multiplied by itself ... Ex: two to the fourth power
4 would be the exponent
The differences is 7 because I counted.
First, find out what the greatest common factor is between 2, 4, and 5.
<span>This is 20. So any number divisible by 20 is also divisible by 2, 4, and 5. </span>
<span>Now we find the list of numbers that are multiples of 20 between 67 and 113. </span>
<span>The solutions are: </span>
<span>80 and 100.</span>
Answer:
x = 8 in
y = 8sqrt(2) in
Step-by-step explanation:
x = 8
AC = BC
Because opposite angles are equal.
8² + 8² = hyp²
hyp² = 64 + 64 = 128
hyp = sqrt(128)
hyp = 8sqrt(2)
Where sqrt is the square root