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kari74 [83]
3 years ago
6

Need the answer ASAP!! 20 points

Mathematics
1 answer:
aniked [119]3 years ago
8 0

Answer:

I think C. is it

Step-by-step explanation:

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A multiple must be greater than or equal to the largest starting number. True or False
podryga [215]

I'll use multiples of 2 and 4 as an example:

Multiples of 2: 2, 4, 6, 8...

Multiples of 4: 4, 8, 12, 16...

The least common multiple in this case is 4. The LCM is always ≥ the largest starting number, which is 4 for this example. Therefore, the statement is true.

<em>Hope this helps! :)</em>

8 0
3 years ago
Malcolm planted two trees in his yard. One tree is 50 inches tall and grows
Evgen [1.6K]
First make an equation for first tree
Y=2x+50
Then second tree
Y=1x+59
Then put them equal to eachother
2x+50=1x+59
Solve by subtracting 1x and then subtracting 50
Answer= x=9
9 months
3 0
3 years ago
Find the quotient. 42j^4k^2/(-3j^3k)
jek_recluse [69]

42j^4k^2/(-3j^3k)

42/-3   * j^4/j^3   *k^2/k

-14 *j *k

3 0
3 years ago
4. Lisa walked 48 blocks in 3 hours.<br> blocks per hour
dlinn [17]

Answer:

The number of blocks in one hour is the same that the unit rate, so 16 blocks per hour

Step-by-step explanation:

we know that

To find out the unit rate, divide the total blocks by the total time

so

\frac{48}{3}\ \frac{blocks}{hours}=16\ \frac{blocks}{hour}

3 0
3 years ago
If x+ay =b and<br> ax-by=c <br> Then find out x , y . (with process)
n200080 [17]

Answer:

The solution of the given system of equations is,

x=\frac{b^2+ac}{a^2+b};\; y=\frac{ab-c}{a^2+b}

Step-by-step explanation:

The given equations are :

<em>x</em> + a<em>y</em> = b          .......(1)

a<em>x</em> - b<em>y</em> = c        .......(2)

We will use 'Substitution Method' to solve the given system of equations.

In this method, we will find out the value of either of the two variables that is '<em>x</em>' and '<em>y</em>' from one of the two equations in terms of the another variable  and then substitute that value in the other equation to find the value of the another variable.

Now, we will be finding out the value of '<em>x</em>' in terms of '<em>y</em>' from equation (1) and then substitute it in the equation (2).

Consider the equation (1), that is,

   <em>x</em> + a<em>y</em> = b ⇒ <em>x</em> = b - a<em>y</em>          ........(3)

Substitute the value of '<em>x</em>' from (3) in (2), we get

  a(b - a<em>y</em>) - b<em>y</em> = c

⇒ab - a²<em>y</em> - b<em>y</em> = c

⇒-a²<em>y</em> - b<em>y</em> = c - ab

⇒-<em>y</em>(a²+b) = c - ab

⇒<em>y</em>(a²+b) = ab - c

\implies y=\frac{ab-c}{a^{2}+b}

Now, substituting the above value of '<em>y</em>' in equation (3), we get

x=b-a(\frac{ab-c}{a^2+b})

\implies x=\frac{b(a^2+b)-a(ab-c)}{a^2+b}

\implies x=\frac{a^2b+b^2-a^2b+ac}{a^2+b}

\implies x = \frac{b^2+ac}{a^2+b}

Hence, the solution of the given system of equations is,

x = \frac{b^2+ac}{a^2+b} ;\; y = \frac{ab-c}{a^2+b}

5 0
3 years ago
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