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2 years ago

PLEASE HELP QUICKLY IM VERY CONFUSED

Mathematics

1 answer:

Harman [31]2 years ago

7 0

Answer:

42/90

Step-by-step explanation:

Let x = .46

multiply both sides by 10

10x = 4.66

multiply both sides by 10 again

100x = 46.66

100x - 10x = 46.66 - 4.66

90x = 42

x = 42 / 90

Can be reduced to x = 21/45

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At the state fair, admission at the gate is $9. In addition, the cost of each ride is $3. Suppose that Deshaun will go on x ride

pshichka [43]

SOLUTION:

Step 1:

In this question, we are given the following:

Step 2:

The details of the solution are as follows:

Step-by-step explanation:

Given :

At the state fair, admission at the gate is $9.

In addition, the cost of each ride is $3.

Suppose that Sam will go on x rides.

Then, cost of x rides ( in dollars) = Cost per ride x Number of rides

=3x

Total cost ( in dollars) : Admission fee + cost of x rides

= 9+3x

Sam wants the total number of dollars he spends on admission and rides to be at most t ( less than or equal to t )

$9\text{ + 3x }\leq\text{ t}$

CONCLUSION:

The final answer is:

Using the values and variables given, write an inequality describing this.

$9\text{ + 3x }\leq\text{ t}$

4 0

1 year ago

Use the disk method or the shell method to find the volumes of the solids generated by revolving the region bounded by the graph

diamong [38]

Answer:

a) 8π

b) 8/3 π

c) 32/5 π

d) 176/15 π

Step-by-step explanation:

Given lines : y = √x, y = 2, x = 0.

a) The x-axis

using the shell method

y = √x = , x = y^2

h = y^2 , p = y

vol = ( 2π ) $\int\limits^2_0 {ph} \, dy$

= $( 2\pi ) \int\limits^2_0 {y.y^2} \, dy$

∴ Vol = 8π

b) The line y = 2 ( using the shell method )

p = 2 - y

h = y^2

vol = ( 2π ) $\int\limits^2_0 {ph} \, dy$

= $( 2\pi ) \int\limits^2_0 {(2-y).y^2} \, dy$

= ( 2π ) * [ 2/3 * y^3 - y^4 / 4 ] ²₀

∴ Vol = 8/3 π

c) The y-axis ( using shell method )

h = 2-y = h = 2 - √x

p = x

vol = $(2\pi ) \int\limits^4_0 {ph} \, dx$

= $(2\pi ) \int\limits^4_0 {x(2-\sqrt{x} ) } \, dx$

= ( 2π ) [x^2 - 2/5*x^5/2 ]⁴₀

vol = ( 2π ) ( 16/5 ) = 32/5 π

d) The line x = -1 (using shell method )

p = 1 + x

h = 2√x

vol = $(2\pi ) \int\limits^4_0 {ph} \, dx$

Hence vol = 176/15 π

attached below is the graphical representation of P and h

3 0

2 years ago

Solve x(x-1) (X-5) <=O

lara [203]

Answer:

x <= 0 or 1 = < x <= 5.

Step-by-step explanation:

First we find the critical points:

x(x - 1)(x - 5) = 0

gives x = 0, x = 1 and x = 5.

Construct a Table of values:

x < 0 x = 0 0< x < 1 1 =< x <= 5 x = 5

x <0 0 >0 <0 0

x - 1 <0 -1 >0 <0 0

x - 5 < 0 0 > 0 <0 0

x(x-1)(x-5) < 0 0 >0 <0 0

So the answers are x =< 0 or 1 =< x <= 5.

8 0

2 years ago

A rectangular plot of farmland will be bounded on one side by a river and on the other three sides by a single-strand electric

larisa86 [58]

Answer:

525 x 1,050

A = 551,250 m²

Step-by-step explanation:

Let 'L' be the length parallel to the river and 'S' be the length of each of the other two sides.

The length of the three sides is given by:

$2S+L=2,100\\ L=2100-2S$

The area of the rectangular plot is given by:

$A=S*L\\A=S(2100-2S)\\A=2100 S -2S^2$

The value of 'S' for which the area's derivate is zero, yields the maximum total area:

$\frac{dA(S)}{dS}=\frac{d(2100 S -2S^2)}{dS}\\0= 2100 - 4S\\S=525$

Solving for 'L':

$L=2100-(2*525)\\L=1,050$

The largest area enclosed is given by dimension of 525 m x 1,050 and is:

$A = 525*1,025\\A=551,250\ m^2$

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3 years ago

Determine whether the point (1, 5) is a solution to the system of equations. Explain your reasoning in complete sentences.

Ivanshal [37]

The solution to any system graphically can be found where the 2 graphs intersect. These two graphs intersect at the point (0, 2).

4 0

3 years ago

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