General equation for height, h
h = ut + 0.5gt^2
at t=1s, h = 76 feet
76 = u*1 + 0.5*a*1^2
76 = u + 0.5a
at t=2s, h = 144 feet
144 = u*2 + 0.5*a*2^2
144 = 2u + 2a
72 = u + a
Subtract 2 equations
0.5a = -4
a = -8
u = 80
So the equation,
h(x) = 80t + 0.5*(-8) t^2
h(x) = 80t - 4t^2
Answer:13 hours
Step-by-step explanation: remember you are averaging so you add the two numbers and divide by the number of numbers, 2. So, 15+11=26, 16 divided by 2=13
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2^n - 3 = 83
<span>2^n = 86 </span>
<span>ln(2^n) = ln(86) </span>
<span>n*ln(2) = ln(86) </span>
<span>n= ln(86)/[ln(2)] (which is the same as "log base 2 of 86") </span>
<span>n= 6.426264755</span>
Answer:
13) x=n-11
15) x=3*10
Step-by-step explanation:
I used x as the variable. The questions are pretty straightforward. They are asking you to put the terms in the description on the right side of the equation. The questions = x. That was probably confusing, but it is correct. I hope this helped!
Left and right side are exactly same, therefore "<span>the equation is true for any value of x.</span>"
Option B
