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aleksley [76]
3 years ago
9

Prove that for all natural numbers n 8n-3n is divisible by 5

Mathematics
2 answers:
Yuri [45]3 years ago
8 0

8n-3n=5n

One of the factors is 5, so the number is divisible by 5.

sertanlavr [38]3 years ago
6 0
8n-3n=n(8-3)=n(5)=5n=5 times n
5 is a factor of 5n so it is evenly divisible by 5
and since n is a natural number, it is the multiplier to make multipules of 5

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So now our equation is:

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