3 years ago

Prove that for all natural numbers n 8n-3n is divisible by 5

Mathematics

2 answers:

Yuri [45]3 years ago

8 0

$8n-3n=5n$

One of the factors is 5, so the number is divisible by 5.

sertanlavr [38]3 years ago

6 0

8n-3n=n(8-3)=n(5)=5n=5 times n
5 is a factor of 5n so it is evenly divisible by 5
and since n is a natural number, it is the multiplier to make multipules of 5

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