Referring to the above 5x=13
Then x=13/5=2.6
For y
2(2.6)+2y=0
Y= -5.2/2=-2.6
X=2.6
Y= -2.6
Answer:
x = 5
Step-by-step explanation:
Start by distributing the 5 to remove parentheses. To do this multiply the numbers and variable in the parentheses by 5.
10x - 20 - 11 = 4 + 3x
Next. you want to get the variables to one side. This is done by subtracting 3x from both sides.
7x - 20 - 11 = 4
Now solve the -20 - 11.
7x - 31 = 4
You need to have the variable all by itself. To do this, first add -31 to both sides.
7x = 35
Finally divide by 7.
x = 5
Hope this helped.
It's a proportion, 65/100 • 39/60. To get this you do 65/100 ( that's the percent) • 39/x. You multiple 100•39 and divide that answer by 65
Answer:
Mean qualifying speed
= 224.5669mi/hr
Speed that passed the average/mean
= 226.240mi/hr ,224.037mi/hr 226.484mi/hr, 225.172 mi/hr
Step-by-step explanation:
Let's understand what mean is then understand what mean qualifying speed is.
First mean is like the average of the seven speed listed below.
So let's find the mean.
Mean = (223.684+ 222.929+ 226.240
+224.037 +226.484+ 225.172
+223.422)/7
Mean = 1571.968/7
Mean = 224.5669
So the mean qualifying speed is those speed that qualifies when the mean is taken, i.e the speed that crossed the average.
Mean qualifying speed are
=226.240 ,224.037,226.484
, 225.172
