Given the equation:
cos²(x) + 9cos(x) = 5cos(x) + 5
cos²(x) + 9cos(x) - 5 cos(x) - 5 = 0
cos²(x) + 4cos(x) - 5 = 0
[cos(x) + 5][cos(x) - 1] = 0
cos (x) = - 5 x ∉ ℝ; so:
cos (x) = 1
Then;
x = 0, and x = 2π
Answer:
Step-by-step explanation:
I think you meant, "what is the value of h(10)." If that's the case, then
h(10) = 6 - 10 = -4
(.75*12)*3= 27 hopefully that’s correct!
Let's look at the way each of these attempts to simplify our expression.
Answer A simply mulltiplies the 4 and the 7 to get 28. <em>This is the correct answer</em>.
The reason you can't just do squaring (to the power of 2) and then go to the power of x later is because you would write that as
, not
.
4x=5x-12
subtract 5x from each side
-x=-12
to get a positive x multiply each side by a -1
x=12
Hope I helped :)