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Nataly_w [17]
2 years ago
13

Forty thousand in numbers​

Mathematics
1 answer:
Lemur [1.5K]2 years ago
5 0

Answer:

40,000

Step-by-step explanation:

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Factor. 49x^2−36y^2 <br> Enter your answer in the boxes.
wel

\\Rewrite \ in \ form.\\\\(7x)^2 - (6y)^2\\\\\\\\Use \ difference \ of \ squares \  rule.\\\\(7x  + 6y) (7x - 6y)\\\\\\Therefore, \ you \ get \fbox{(7x+6y)&(7x-6y)}.

3 0
3 years ago
Three vectors A, B, C in three-dimensional space satisfy the following properties
wlad13 [49]

Answer:

\frac{7}{8}\pi

Step-by-step explanation:

observe

||a–b+c|| = ||a+b+c||

(a-b+c)² = (a+b+c)²

(a+b+c)² – (a-b+c)² = 0

((a+b+c)+(a-b+c))((a+b+c)–(a-b+c)) = 0

(2a+2c)(2b) = 0

(a+c)b = 0

a•b + c•b = 0

||a||×||b||×cos(π/8) + ||c||×||b||×cos(θ) = 0

\cos(\theta)=-\frac{||a||\times ||b|| \times \cos(\frac{\pi}{8})}{||c||\times ||b||}=-\cos(\frac{\pi}{8})\\ \theta=\frac{7}{8}\pi

3 0
3 years ago
Which of the following represent independent events? Spinning a 3 on a spinner and then spinning again and getting a 2. Getting
babymother [125]

Answer:

huh?

Step-by-step explanation:

4 0
3 years ago
Eric, Cam, and Brooke are playing mini golf on a computer. The game stores objects in terms of x xx- and y yy-coordinates. The g
svetlana [45]

Answer:

Its Eric 9.8m

Step-by-step explanation:

5 0
3 years ago
WILL GIVE BRAINLIEST IF CORRECT ANSWER!!!
Rom4ik [11]

Answer : 2√3

<u>Given </u><u>:</u><u>-</u>

  • A equilateral triangle with side length 4.

<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>

  • The value of x in the given figure.

As we know that in a equilateral triangle , perpendicular bisector , angle bisector and median coincide with each other .

  • So the perpendicular drawn in the figure will bisect the given side .
  • Therefore the value of each half will be 4/2 = 2 .

Now we may use Pythagoras theorem as ,

→ AB² = BC² + AC²

→ 4² = 2² + x²

→ 16 = 4 + x²

→ x² = 16-4

→ x² = 12

→ x =√12 = √{ 3 * 2²}

→ x = 2√3

<u>Hence </u><u>the</u><u> required</u><u> answer</u><u> is</u><u> </u><u>2</u><u>√</u><u>3</u><u> </u><u>.</u>

I hope this helps.

3 0
2 years ago
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