Answer:
-176.........................
With a given parallel line and a given point on the line
we can use the point-line method: y-y0=m(x-x0)
where
y=mx+k is the given line, and
(x0,y0) is the given point.
Here
m=-10, k=-5, (x0,y0)=(-3,5)
=> the required line L is given by:
L: y-5=-10(x-(-3))
on simplification
L: y=-10x-30+5
L: y=-10x-25
Answer:

Step-by-step explanation:
we know that
If two lines are parallel then their slopes are equal
The equation of the given line is

the slope is 
so
the slope of the parallel line to the given line is also 
Find the equation of the line that is parallel to the given line and passes through the point (6, 5)
we have


The equation of the line in point slope form is

substitute

Convert to slope intercept form

isolate the variable y



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