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sesenic [268]
3 years ago
7

Refer to the picture given below to give the answer. Don’t forget to use the correct amount of sig figs.

Chemistry
1 answer:
kumpel [21]3 years ago
7 0

Answer:

9.62 μm

Explanation:

From the question given above, the following data were obtained:

Frequency (f) = 31.2 THz

Wavelength (λ) =..?

Next, we shall convert 31.2 THz to Hz.

This can be obtained as follow:

Recall:

1 THz = 1×10¹² Hz

Therefore,

31.2 THz = 31.2 THz × 1×10¹² Hz / 1 THz

31.2 THz = 3.12×10¹³ Hz

Therefore, 31.2 THz is equivalent to 3.12×10¹³ Hz.

Finally, we shall determine the wavelength (λ) infrared radiation as follow:

Frequency (f) = 3.12×10¹³ Hz.

Velocity (v) = 3×10⁸ m/s

Wavelength (λ) =..?

V = λf

3×10⁸ = λ × 3.12×10¹³

Divide both side by 3.12×10¹³

λ = 3×10⁸ / 3.12×10¹³

λ = 9.62×10¯⁶ m

Converting 9.62×10¯⁶ m to micro metre (μm) we have:

1 m = 1×10⁶ μm

Therefore,

9.62×10¯⁶ m = 9.62×10¯⁶ m × 1×10⁶ μm / 1 m

9.62×10¯⁶ m = 9.62 μm

Therefore, the wavelength of the infrared radiation is 9.62 μm

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Which part of the flower produces seeds? (992 points)
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Answer:

The pistil, B.

Explanation:

The seeds are formed from the ovule which is contained in the ovary; all in the base, the pistil.

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3 years ago
What happens when you mix baking powder baking soda and hydrogen peroxide together?
katen-ka-za [31]
Its just like backing soda and viniger i think hope that helped

8 0
3 years ago
What is missing from this graph?<br><br> A. axis labels<br> B. a trendline<br> C. a title
Iteru [2.4K]

Answer:

Axis Labels

Explanation:

The axis labels are usually located on the x and y axis. This graph however is missing those.

hope this helps!

7 0
3 years ago
Which piece of equipment would be used to measure the volume of liquid
cestrela7 [59]
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3 0
3 years ago
A 35.161 mg sample of a chemical known to contain only carbon, hydrogen, sulfur, and oxygen is put into a combustion analysis ap
xxMikexx [17]

Answer:

The empirical formulae is C6H12S02

Explanation:

1. First we need to obtain the mass of each element in the sample and compound formed

Carbon = (62.637 mg * 12.011 g/mol / 44.009 g/mol) = 17.094 mg of Carbon

Hydrogen = ( 25.641 mg * (2 *1..008 g/mol) / 18.015 g/mol) = 2.869 mg of Hydrogen

Sulphur = (13.54 mg * 32.066 g/mol / 64.066 g/mol) = 6.777 mg of Sulphur

2. Next is to determine the percentage composition. Here we divide the respective mass by the mass of the sample

Carbon = 17.094 / 35.161 * 100 = 48.62 %

Hydrogen = 2.869/ 35.161 *100 = 8.16 %

Sulphur = 6.777/ 31.321 *100 = 21.64 %

Oxygen = (100 - (48.62 + 8.16 + 21.64)) = 21.58 %

3. Next is to divide the mass assuming there are 100 mg by the respective atomic masses to obtain the number of moles

Carbon = 48.62 / 12.011 = 4.048 mol

Hydrogen = 8.16 / 1.008 = 8.095 mol

Sulphur = 21.64 / 32.066 = 0.675 mol

Oxygen = 21.58 / 16.000 = 1.348 mol

Next is to divide by the smallest value

Carbon = 4.048/ 0.675 =5.997 = 6

Hydrogen = 8.095 / 0.675 =11.993 =12

Sulphur = 0.675/ 0.675 = 1

Oxygen = 1.348 / 0.675 = 1.997 = 2

So therefore the empirical formulae of the sample is C6H12SO2

7 0
3 years ago
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