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mojhsa [17]
2 years ago
9

What is missing from this graph? A. axis labels B. a trendline C. a title

Chemistry
1 answer:
Iteru [2.4K]2 years ago
7 0

Answer:

Axis Labels

Explanation:

The axis labels are usually located on the x and y axis. This graph however is missing those.

hope this helps!

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Chicken nuggets

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Really strong acids and bases are found at the​
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3 years ago
What is the melting point of a substance?
Alona [7]

Answer:

The answer is C) The temperature at which the solid-state turns into liquid

Explanation:

The melting point of a substance is the temperature at which it shifts state from solid to liquid. At the melting point, the solid and liquid levels exist in equilibrium. As heat is applied to a solid, its temperature will increase until the melting point is reached. More heat then will convert the solid into a liquid with no temperature change. This occurs when the internal energy of the solid increases, commonly by the application of heat or pressure, which increases the substance's temperature to the melting point.

6 0
2 years ago
When water changes state from a liquid to a solid is energy absorbed or lost?
Brrunno [24]

Answer:

Loses

Explanation:

liquid changes into solid, heat is released. The energy released upon freezing, known as the enthalpy of fusion, is a latent heat, and is exactly the same as the energy required to melt the same amount of the solid.

4 0
3 years ago
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Calcium hydroxide is a strong base but is not very soluble ( Ksp = 5.02 X 10-6 ). What is the pH of a saturated solution of Ca(O
Misha Larkins [42]

Answer : The pH of a saturated solution is, 12.33

Explanation : Given,

K_{sp} = 5.02\times 10^{-6}

First we have to calculate the solubility of OH^- ion.

The balanced equilibrium reaction will be:

Ca(OH)_2\rightleftharpoons Ca^{2+}+2OH^-

Let the solubility will be, 's'.

The concentration of Ca^{2+} ion = s

The concentration of OH^- ion = 2s

The expression for solubility constant for this reaction will be,

K_{sp}=[Ca^{2+}][OH^-]^2

Let the solubility will be, 's'

K_{sp}=(s)\times (2s)^2

K_{sp}=(4s)^3

Now put the value of K_[sp} in this expression, we get the solubility.

5.02\times 10^{-6}=(4s)^3

s=1.079\times 10^{-2}M

The concentration of Ca^{2+} ion = s = 1.079\times 10^{-2}M

The concentration of OH^- ion = 2s = 2\times (1.079\times 10^{-2}M)=2.158\times 10^{-2}M

First we have to calculate the pOH.

pOH=-\log [OH^-]

pOH=-\log (2.158\times 10^{-2})

pOH=1.67

Now we have to calculate the pH.

pH+pOH=14\\\\pH=14-pOH\\\\pH=14-1.67=12.33

Therefore, the pH of a saturated solution is, 12.33

7 0
3 years ago
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