This is a quadrilateral, so the sum of interior angle measures, like a rectangle or square ( who’s interior angle measures are4 x 90) —— is 360
So ...
E + 89 + 130 + 90 = 360
E + 309 = 360
- 309 - 309
E = 51 degrees
7 - 2 (7) -8
7 - 14 - 8
7-14= -7
-7 - 8 = - 15
May have messed this one up
Now if we have 7.5 pounds of apples first we need to convert 1 pound into ounces.
1 pound = 16 ounces.
Now we know how many ounces are in one pound. So lets take the 16 ounces for 1 pound and multiply by the 7 full pounds of apples. This excluding the 1/2 pound of apples.
7 x 16 = 112
(7 being the weight in pounds of the apples, 16 being 16 ounces in one pound, and 112 is how any ounces are in 7 pounds of apples.)
So now we have the amount of ounces in 7 pounds of apples.
But we are not done. We still have the 1/2 pound of apples. So we take 16 being 1 pound of apples and divide it by 2.
16 divided by 2 = 8
That 1/2 pound of apples = 8 ounces.
So now we have our 7 pounds of apples in ounces (112) and our 1/2 pound of apples in ounces (8)
So we add these back up in ounces
112 + 8 = 120.
So now we can conclude:
7.5 pounds of apples is 120 ounces
Hope this helps!
Brainliest is always appreciated if you feel its deserved! :)
Answer:
okay
Step-by-step explanation:
the probability of choosing blue marble is
p(blue)= 4/14
Answer:
The 85% onfidence interval for the population proportion of new car buyers who prefer foreign cars over domestic cars is (0.151, 0.205).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:
Sample of 421 new car buyers, 75 preferred foreign cars. So 
85% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 85% onfidence interval for the population proportion of new car buyers who prefer foreign cars over domestic cars is (0.151, 0.205).