Factorize completely<br>- 3a² + 4a + 4<br>

Please help which one is the answer

drek231 [11]

Answer:

The second bubble

Explanation

You need to make your exponents equal the other side so to do this;

Distribute the 3 in the exponent "3(x-2)"

Which is 3x-6

And since multiplying exponents adds them, you need a -6 to make the two equal.

So your exponent should equal -6 to make that statement true

6 0

3 years ago

A tank fills in 8 hours but evaporates in 12. how long will it take to fill the tank

Neko [114]

1 = h · $\frac{1}{8}$ - h · $\frac{1}{12}$

Solve for h.
(units in hours)

7 0

3 years ago

At the fall festival, there was a pumpkin picking contest. The 6th grade team picked 16 pumpkins in 4 minutes, and the seventh g

VikaD [51]

Answer:

7th grade team

Step-by-step explanation:

6th grade team: 16/4= 4 pumpkins per min

7th grade team: 48/8= 6 pumpkins per min

Therefore, the 7th grade team picked more pumpkins per min

6 0

3 years ago

Read 2 more answers

Choose the function with the largest constant of variation? A 2-column table with 5 rows. Column 1 is labeled x with entries 1,

Zielflug [23.3K]

Answer:

A reasonable way to use them is to code the five most-common strings in the ... bytes, compared to a bitmap size of only 6 × 8 bits = 6 bytes. ... Columns 2, 4, 5, and 7 yield the six runs 0,5,1,1,1,eol each. ... 2.3: Replacing 10 by 3 we get x = k log2 3 ≈ 1.58k. ... Table Ans.3: Probabilities and Entropies of Two Symbols.

Step-by-step explanation:

?

3 0

3 years ago

Read 2 more answers

An Archer shoots an arrow horizontally at 250 feet per second. The bullseye on the target and the arrow are initially at the sam

Genrish500 [490]

Answer:

Step-by-step explanation:

Using the formula for finding range in projectile, Since range is the distance covered in the horizontal direction;

Range $R = U\sqrt{\frac{H}{g} }$

U is the velocity of the arrow

H is the maximum height reached = distance below the bullseye reached by the arrow.

R is the horizontal distance covered i.e the distance of the target from the archer.

g is the acceleration due to gravity.

Given R = 60ft, U = 250ft/s, g = 32ft/s H = ?

On substitution,

$60 = 250\sqrt{\frac{H}{32}} \\\frac{60}{250} = \sqrt{\frac{H}{32}}\\\frac{6}{25} = \sqrt{\frac{H}{32}$

Squaring both sides we have;

$(\frac{6}{25} )^{2} = (\sqrt{\frac{H}{32} } )^{2} \\\frac{36}{625} = \frac{H}{32} \\625H = 36*32\\H = \frac{36*32}{625} \\H = 1.84feet$

The arrow will hit the target 1.84feet below the bullseye.

5 0

3 years ago

Factorize completely- 3a² + 4a + 4​

Factorize completely- 3a² + 4a + 4