There are two steps to this problem. The first step is to make an equation for the cost of each company. The cost of each one involves 2 variables. However, we can ignore the number of days since the question asks for per day.
CostA = 90 + .40(miles)
CostB = 30 + .70(miles)
We want to know when A is a better deal or when A costs less. That is when CostA < CostB. We can then substitute the right sides of our equations into the inequality. This will give:
90 + .40(miles) < 30 + .70(miles) This is where we will now begin to solve for the number of miles.
-30 -30 Subtract 30 from both sides.
60 + .4(miles) < .7(miles) Simplify
-.4(miles) -.4(miles) Subtract .4(miles) from both sides
60 < .3(miles) Simplify
/.3 /.3 Divide both sides by .3
200 < miles Simplify
So for A to cost less the number of miles must be greater than 200.
How do I find the Q1 and Q3?<br><br>
0,0,1,2,2,3,4,4,4,4,5,6,6,7,7
Angelina_Jolie [31]
Answer:
Q1 = 2
Q3 = 6
Step-by-step explanation:
Mathematically, we have
Q1 = (n + 1)/4 th term
where n is the number of terms
By the count, we have n as 15
Q1 = (15 + 1)/4
Q1 = 4th term
Looking at the arrangement, the 4th term is 2
For Q3
Q3 = 3(n + 1)/4 th term
n = 15
Q3 = 3 * 4 = 12th term
The 12th term is 6
So that is the 3rd quartile
The answer is 32. You have four trays each have 8 bars so multiply 8 and 4.
8*4=32
Answer:
=6 units squared
Step-by-step explanation:
area=1/2h(a+b)
=1/2×2(4+2)
=6
Answer:
x=13 y=10 z=3 d) 260
Step-by-step explanation:
vertex angles are congruent so you can set them equal to each other and solve
and then a straight like adds up to 180 so 180-(7(x-3)+5y)= your missing angle and then that angles is congruent to its opposite so 2(5z+15)=60
