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3 years ago

The differences between the data points and the estimated regression line are called the

1 answer:

8 0

Linear regression is a method of finding the linear equation that comes closest to fitting a collection of data points.
The better the choice of line, the closer the predicted values will be to the observed values.
The differences between the data pints (observed values) and the estimated (pedicted) regression line is called the residue.
Residue = Observed Value - Predicted Value

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Use elimination to solve the system of equations:

zhenek [66]

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8 0

3 years ago

Find the critical value of x2 based on the given information H1 >3.5 n=14 a=0.05

egoroff_w [7]

Answer:

The degrees of freedom are given by:

$df = n-1=14-1=13$

The significance level is $\alpha=0.05$ and then the critical value can be founded in th chi square table we need a quantile that accumulates 0.05 of the area in the right tail of the distribution and for this case is:

$\chi^2_{\alpha}= 22.362$

And if the chi square statistic is higher than the critical value we can reject the null hypothesis in favor of the alternative.

Step-by-step explanation:

We have the followign system of hypothesis:

Null hypothesis: $\sigma^2 \leq 3.5$

Alternative hypothesis: $\sigma^2 >3.5$

The degrees of freedom are given by:

$df = n-1=14-1=13$

$\chi^2_{\alpha}= 22.362$

And if the chi square statistic is higher than the critical value we can reject the null hypothesis in favor of the alternative.

4 0

3 years ago

A system of equations is shown below. Which of the following statements describes the graph of this system of equations in the (

katovenus [111]

Answer:

Step-by-step explanation:

3y - 5x = 15 ... A

y = 5/3 * X +15 .... slope 3/5 , y intercept 15

6y - 10x =30

(6y - 10x) /2 = 30 / 2

3y - 5x = 15 ... B

y = 5/3 * x + 15 ..... slope 3/5 , y intercept 15

∴ Answer is C

7 0

3 years ago

Read 2 more answers

Consider a system with one component that is subject to failure, and suppose that we have 115 copies of the component. Suppose f

castortr0y [4]

Answer:

Step-by-step explanation:

From the given information:

the mean $(\mu) = 115 \times 20$

= 2300

Standard deviation = $20 \times \sqrt{115}$

Standard deviation (SD) = 214.4761

TO find:

a) $P(x > 3500)= P(Z > \dfrac{3500-\mu}{214.4761})$

$P(x > 3500)= P(Z > \dfrac{3500-2300}{214.4761})$

$P(x > 3500)= P(Z > \dfrac{1200}{214.4761})$

$P(x > 3500)= P(Z >5.595)$

From the Z-table, since 5.595 is > 3.999

$P(x > 3500)=1-0.9999$

P(x > 3500) = 0.0001

Here, the replacement time for the mean $(\mu) = \dfrac{0+0.5}{2}$

= 0.25

Replacement time for the Standard deviation $\sigma = \dfrac{0.5-0}{\sqrt{12}}$

$\sigma = 0.1443$

For 115 component, the mean time = (115 × 20)+(114×0.25)

= 2300 + 28.5

= 2328.5

Standard deviation = $\sqrt{(115\times 20^2) +(114\times (0.1443)^2)}$

= $\sqrt{(115\times 400) +(114\times 0.02082249}$

= $\sqrt{(46000) +2.37376386}$

= $\sqrt{(46000) +(2.37376386)}$

= $\sqrt{46002.374}$

= 214.482

Now; the required probability:

$P(x > 4125) = P(Z > \dfrac{4125- 2328.5}{214.482})$

$P(x > 4125) = P(Z > \dfrac{1796.5}{214.482})$

$P(x > 4125) = P(Z >8.376)$

$P(x > 4125) =1- P(Z$

From the Z-table, since 8.376 is > 3.999

P(x > 4125) = 1 - 0.9999

P(x > 4125) = 0.0001

7 0

3 years ago

Use a model to solve 13 x 4/9 . Leave your answer as an improper fraction.

ivanzaharov [21]

Step-by-step explanation:

13×4/9=52/9

answer as improper fraction is 52/9

3 0

2 years ago

Read 2 more answers