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3 years ago

What is not an example of a linear equation

Mathematics

2 answers:

Fiesta28 [93]3 years ago

8 0

Answer: Linear Equations do NOT have: Exponents

Yuliya22 [10]3 years ago

8 0

Answer:

3x+2y=10

Step-by-step explanation:

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Nadya [2.5K]

Answer:

find the cubic root of the number given

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3 years ago

52/21 in its simplest form as a mixed number

Sliva [168]

Answer:

$2\frac{10}{21}$

Step-by-step explanation:

1. find out how many times 21 can go into 52 (answer- 2 times)

2. find the remainder (answer- 10)

3. put the remainder over 21 (10/21)

4. make it a mixed number (2 10/21)

7 0

4 years ago

Please I really need help answer question 2.

kati45 [8]

Let the number of CD's be x and total cost be y

y=7x-10

*the 7 comes from the price of each individual CD ($7)
*the 10 comes from the discount ($10)

4 0

3 years ago

. You are interested in the amount of time teenagers spend weekly working at part-time jobs. A random sample of 15 teenagers was

agasfer [191]

Answer:

$t=\frac{147.3-120}{\frac{50}{\sqrt{15}}}=2.115$

Now we can calculate the degrees of freedom

$df=n-1=15-1=14$

If we find a critical value in the t distribution with 14 degrees of freedom who accumulates 0.05 of the area in the right we got $t_{critc}= 1.761$

Since the calculated value is higher than the critical value we have enough evidence to conclude that the true mean is significantly higher than 120 minutes for the average time of part time jobs

Step-by-step explanation:

Information given

$\bar X=147.3$ represent the sample mean for the amount of time spent at part time jobs

$s=50$ represent the sample standard deviation

$n=15$ sample size

$\mu_o =120$ represent the value to check

$\alpha=0.05$ represent the significance level

t would represent the statistic

$p_v$ represent the p value for the test

System of hypothesis

We want to analyze if the true mean for the amount of time spent at part time jobs is higher than 120, the system of hypothesis would be:

Null hypothesis: $\mu \leq 120$

Alternative hypothesis: $\mu > 120$

Since we don't know the population deviation the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{147.3-120}{\frac{50}{\sqrt{15}}}=2.115$

Now we can calculate the degrees of freedom

$df=n-1=15-1=14$

If we find a critical value in the t distribution with 14 degrees of freedom who accumulates 0.05 of the area in the right we got $t_{critc}= 1.761$

Since the calculated value is higher than the critical value we have enough evidence to conclude that the true mean is significantly higher than 120 minutes for the average time of part time jobs

4 0

3 years ago

Which system of equations is equivalent to the system of equations shown?

tino4ka555 [31]

x+y= 4 (-2)
3x+2y = 9

-2x -2y = -8
3x +2y = 9
x = 1

1+y =9
y = 9-1
y =8

7 0

4 years ago

Read 2 more answers