Answer:
∠a = 42.5°
∠b = 87°
∠c = 174°
∠d = 90°
∠f = 131°
Step-by-step explanation:
∠a = 85°/2 = 42.5°
∠b = 360° -110° - 76° = 174°/2 = 87°
∠c = 360° -110° - 76° = 174°
∠d = 90°
∠f = 360° - 101° - (64° x 2) = 131°
The practical domain of time is t ∈ [0, 4.25s].
- The set of values that make feel in a particular context is referred to as the sensible area.
- All feasible solutions are addressed by way of theoretical domains and stages.
- domain names and stages restrict the solution sets such that they may be realistic in the parameters given
- .The ball begins its motion at time t = 0s.
- To locate the time while the ball hits the floor,
- we solve the equation:
- h(t) = -16t² + 68t
- h(t) = 0
- -16t² + 68t = 0
- t(-16t + 68) = 0
- t = 0 and -16t + 68 = 0.
- 16t = 68
- t = 68/16
- t = 4.25
- h(t) is non-negative within the interval [0, 4.25].
- Hence, the practical domain is 0 ≤ t ≤ 4.25 s.
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Answer:
add them then multiply
Step-by-step explanation:
No U ( ͡° ͜ʖ ͡° ) ( ͡° ͜ʖ ͡° )
