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GrogVix [38]
3 years ago
6

Rhett made a simple drawing of his house.It is a three-dimensional figure with four faces that are rectangular and two that are

square. What kind of figure is it.
Mathematics
1 answer:
marta [7]3 years ago
5 0

Answer:

it is a rectangular prism

Step-by-step explanation:

it is 3D and when something has four faces that are rectangular and two that are sqaure it makes it a rectangular prism. imagine the rectangles on the sides and sqares at the end, it looks like a rectangle =).

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suppose that Y and Z are points on the number line if YZ=11 and Y lies on -9 where would Z be located
PIT_PIT [208]
Z would be located on 2, since (9+2 =11)
4 0
2 years ago
Use stoke's theorem to evaluate∬m(∇×f)⋅ds where m is the hemisphere x^2+y^2+z^2=9, x≥0, with the normal in the direction of the
ludmilkaskok [199]
By Stokes' theorem,

\displaystyle\int_{\partial\mathcal M}\mathbf f\cdot\mathrm d\mathbf r=\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S

where \mathcal C is the circular boundary of the hemisphere \mathcal M in the y-z plane. We can parameterize the boundary via the "standard" choice of polar coordinates, setting

\mathbf r(t)=\langle 0,3\cos t,3\sin t\rangle

where 0\le t\le2\pi. Then the line integral is

\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=0}^{t=2\pi}\mathbf f(x(t),y(t),z(t))\cdot\dfrac{\mathrm d}{\mathrm dt}\langle x(t),y(t),z(t)\rangle\,\mathrm dt
=\displaystyle\int_0^{2\pi}\langle0,0,3\cos t\rangle\cdot\langle0,-3\sin t,3\cos t\rangle\,\mathrm dt=9\int_0^{2\pi}\cos^2t\,\mathrm dt=9\pi

We can check this result by evaluating the equivalent surface integral. We have

\nabla\times\mathbf f=\langle1,0,0\rangle

and we can parameterize \mathcal M by

\mathbf s(u,v)=\langle3\cos v,3\cos u\sin v,3\sin u\sin v\rangle

so that

\mathrm d\mathbf S=(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv=\langle9\cos v\sin v,9\cos u\sin^2v,9\sin u\sin^2v\rangle\,\mathrm du\,\mathrm dv

where 0\le v\le\dfrac\pi2 and 0\le u\le2\pi. Then,

\displaystyle\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S=\int_{v=0}^{v=\pi/2}\int_{u=0}^{u=2\pi}9\cos v\sin v\,\mathrm du\,\mathrm dv=9\pi

as expected.
7 0
3 years ago
What type of right triangle would you use this formula for and why? <br><br>c=2a​
levacccp [35]

Answer:

30 60 90 triangle

the hypotenuse is twice the length of the shorter leg length.

7 0
3 years ago
Please help!!! i’ll give brainliest.
S_A_V [24]

Answer:

quadrilateral ABCD is not congruent to quadrilateral KLMN. quadrilateral ABCD cannot be mapped onto quadrilateral KLMN through a series of rotations, reflections or translations.

7 0
3 years ago
X Y
goldfiish [28.3K]
Range R={-3-11,1,17}
domain D={-9,-3,5}
4 0
3 years ago
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