PLEASE HELP!!!!!!!!!!!

Ramon has applied to MBA programs at both Harvard and Stanford. He thinks the probability that Harvard will admit him is 0.5, th

ivolga24 [154]

Answer:

(a) The Venn diagram is attached below.

(b) The probability that neither university admits Ramon is 0.20.

(c) The probability that Ramon gets into Stanford but not Harvard 0.30.

Step-by-step explanation:

Let's denote the events as follows:

<em>H</em> = Ramon gets admitted to Harvard

<em>S</em> = Ramon gets admitted to Stanford.

The information provided is:

P (H) = 0.50

P (S) = 0.50

P (H ∩ S) = 0.20

(a)

The Venn diagram is attached below.

(b)

Compute the probability that Ramon gets admitted in neither Harvard nor Stanford as follows:

$P(H^{c}\cup S^{c})=1-P(H\cup S) \\= 1 - [P(H)+P(S)-P(H\cap S)]\\=1-[0.50+0.50-0.20]\\=1-0.80\\=0.20$

Thus, the probability that neither university admits Ramon is 0.20.

(c)

Compute the probability that Ramon gets admitted in Stanford but not in Harvard as follows:

$P(H^{c}\cup S)=P(S)-P(H\cap S) \\= 0.50-0.20\\=0.30$

Thus, the probability that Ramon gets into Stanford but not Harvard 0.30.

7 0

3 years ago

Calculate the double integral. $$\iint_{R}{\color{red}4} xye^{x^{2}y}\hspace*{3pt}dA, \quad R = [0, 1] \times [0, {\color{red}7}

Lady_Fox [76]

Answer:

$\mathbf{\int \int _R \ 4xy e^{x^2 \ y} \ dA = 2 (e^7 -8)}$

Step-by-step explanation:

Given that:

$\int \int _R 4xye^{x^2 \ y} \ dA, R = [0,1]\times [0,7]$

The rectangle R = [0,1] × [0,7]

R = { (x,y): x ∈ [0,1] and y ∈ [0,7] }

R = { (x,y): 0 ≤ x ≤ 1 and 0 ≤ x ≤ 7 }

$\int \int _R \ 4xy e^{x^2 \ y} \ dA = \int^{7}_{0}\int^{1}_{0} 4xye^{x^2 \ y} \ dx dy$

$\int \int _R \ 4xy e^{x^2 \ y} \ dA = \int^{7}_{0} \begin {bmatrix} ye^{yx^2} \dfrac{4}{2y} \end {bmatrix}^1 _ 0 \ dy$

$\int \int _R \ 4xy e^{x^2 \ y} \ dA = \int^{7}_{0} \begin {bmatrix} ye^{y1^2} \dfrac{4}{2y} - ye^{y0^2} \dfrac{4}{2y} \end {bmatrix}\ dy$

$\int \int _R \ 4xy e^{x^2 \ y} \ dA = \int^{7}_{0} \dfrac{4}{2}(e^y -1) \ dy$

$\int \int _R \ 4xy e^{x^2 \ y} \ dA = \dfrac{4}{2}[e^y -1]^7_0 \ dy$

$\int \int _R \ 4xy e^{x^2 \ y} \ dA = 2 [(e^7 -7)-(e^0 -0)]$

$\int \int _R \ 4xy e^{x^2 \ y} \ dA = 2 [(e^7 -7)-1]$

$\mathbf{\int \int _R \ 4xy e^{x^2 \ y} \ dA = 2 (e^7 -8)}$

3 0

4 years ago

The equation 5m = 36.25 models a constant rate situation. Drag and drop the value of 7m in the box. 7m =

liberstina [14]

Answer:

7m=50.75 is your answer.

Step-by-step explanation:it is 50.75 because 5m=36.25 so you divide 5 on both sides to cancel out the 5 on the left side so you do 36.25 divided by 5 and you get 7.25 so then you multiply 7.25 times 7 and you get 50.75.

5 0

3 years ago

How many seconds will it take to get a seriously injured inmate to a medical center if the distance between the two points is 48

gizmo_the_mogwai [7]

Answer:

He will require 5400 seconds

Step-by-step explanation:

Given:

The total distance he has to cover = 48 miles

The speed he is moving = 32 mph

To find :

Time in seconds = ?

Solution:

As given in the question that he is moving with a constant speed of 32 mph and he has to cover a distance of 48 miles at this speed so we will be using distance formula for finding the time taken by him

Formula is

Distance = speed * time

here we have to find time so

Time = $\frac{Distance}{speed}$

Putting in the values we get

Time = $\frac{48}{32}$

Dividing it gives us

Time = 1.5 hours

As we need the answer in seconds and we know that

one hour has = 3600 seconds

so

Time = 1.5 * 3600 seconds

Time = 5400 seconds

7 0

4 years ago

What is the measure of the exterior angle?

valina [46]

the answer is 130 degrees, the 2 interior bottom angles are = to one another so 65 and 65, adding them up makes it 130, then 180 - 130 = 50, meaning the top interior angle is 50 degrees, then 180 - 50 is 130.

8 0

3 years ago