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3 years ago

PLEASE HELP!!!!!!!!!!!

Mathematics

1 answer:

Shkiper50 [21]3 years ago

6 0

Hello!

7/11 = 0/63636363...

The answer is B) 7/11

Hope this helps!

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Tremaine: wants a one bedroom townhouse in a trendy new development downtown; average cost is $145,000 is preapproved for a 4.38

Lina20 [59]

Using the monthly payment formula, it is found that the amount he will have to pay each month is of $649.45.

<h3>What is the monthly payment formula?</h3>

It is given by:

$A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}$

In which:

P is the initial amount.

r is the interest rate.

n is the number of payments.

In this problem, considering that the down payment does not count for interest, the parameters are given as follows:

P = 130000, r = 0.0438, n = 30 x 12 = 360.

Then:

r/12 = 0.0438/12 = 0.00365 -> 1+r = 1.00365.

Then the monthly payment is given by:

$A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}$

$A = 130000\frac{0.00365(1.00365)^{365}}{(1.00365)^{365} - 1}$

A = 649.45.

More can be learned about the monthly payment formula at brainly.com/question/2151013

#SPJ1

3 0

2 years ago

Write the equation of a polynomial of degree 3, with zeros 1, 2 and -1 where f(0)=2

drek231 [11]

<u>Answer:</u>

The equation of a polynomial of degree 3, with zeros 1, 2 and -1 is $x^{3}-2 x^{2}-x+2=0$

<u>Solution:</u>

Given, the polynomial has degree 3 and roots as 1, 2, and -1. And f(0) = 2.

We have to find the equation of the above polynomial.

We know that, general equation of 3rd degree polynomial is

$F(x)=x^{3}-(a+b+c) x^{2}+(a b+b c+a c) x-a b c=0$

where a, b, c are roots of the polynomial.

Here in our problem, a = 1, b = 2, c = -1.

Substitute the above values in f(x)

$F(x)=x^{3}-(1+2+(-1)) x^{2}+(1 \times 2+2(-1)+1(-1)) x-1 \times 2 \times(-1)=0$

$\begin{array}{l}{\rightarrow x^{3}-(3-1) x^{2}+(2-2-1) x-(-2)=0} \\ {\rightarrow x^{3}-(2) x^{2}+(-1) x-(-2)=0} \\ {\rightarrow x^{3}-2 x^{2}-x+2=0}\end{array}$

So, the equation is $x^{3}-2 x^{2}-x+2=0$

Let us put x = 0 in f(x) to check whether our answer is correct or not.

$\mathrm{F}(0) \rightarrow 0^{3}-2(0)^{2}-0+2=2$

Hence, the equation of the polynomial is $x^{3}-2 x^{2}-x+2=0$

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3 years ago

A planet has an average distance to the sun of 0.66 AU.<br> How do you calculate it?

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We can calculate that by the Parallax method..........

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4 years ago

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In geometry you can use deductive rules to

Licemer1 [7]

Answer:

To prove that a given statement or conjuncture is true or false using deductive reasoning.

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3 years ago

(3a ^3)^x = 27a^9<br> what’s the value of x?

uysha [10]

Answer:

Step-by-step explanation:

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3 years ago