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3 years ago

A rectangle with an area of 22 - 16.3 + 60 square units could have which possible dimensions?

Mathematics

1 answer:

Burka [1]3 years ago

8 0

Answer:

wasdwasdwasdwasdadadasdasadwawdawwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwsssssssadwasdwa

Step-by-step explanation:

You might be interested in

Solve for the indicated variable (y) 9x+y=7

Gnesinka [82]

1. Slope=9
2. x-intercept = 7/9 = 0.77778
3. y-intercept = 7/-1= -7.00000
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation: 9*X-Y-(7)=0
Hope this helps

7 0

3 years ago

How do you solve 36 times <img src="https://tex.z-dn.net/?f=%5Csqrt%7B3%7D" id="TexFormula1" title="\sqrt{3}" alt="\sqrt{3}" ali

pantera1 [17]

Answer:

62.3538

Step-by-step explanation:

There is nothing to solve. If you need a decimal value, you can use a calculator or table of square roots.

8 0

3 years ago

briana house is at (1,6) and jordan house is(5,3) what is one possible path from brianna house to jordan house

Maurinko [17]

Answer:

see the explanation

Step-by-step explanation:

Let

A (1,6)------> location Brianna's house on a map

B (5,3)------> location Jordan's house on a map

we know that

One possible path from Brianna's house to Jordan's house it's a straight line ( the shortest distance)

using a graph tool

see the attached figure

Find the distance points AB

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

substitute the values

$d_A_B=\sqrt{(3-6)^{2}+(5-1)^{2}}$

$d_A_B=\sqrt{(-3)^{2}+(4)^{2}}$

$d_A_B=\sqrt{25}$

$d_A_B=5\ units$

The distance from Brianna's house to Jordan's house is 5 units

6 0

3 years ago

Rewrite in simplest terms : 9(-8d - 7 ) +6(d+7)

Pepsi [2]

Answer: -66d-21 I think.

Step-by-step explanation:

9(-8d-7)+6(d+7)

-72d-63+6d+42 Distributive Property

-72d+6d+-63+42 Combine Like Terms

-66d-21 Answer

8 0

2 years ago

Which function has the same y-intercept as the function y equals 2/3 x - 3

aleksley [76]

We have the function $y = \frac{2}{3} x -3$ and we want to find a function that has the same y-intercept than the previous function.

First, let's find the y-intercept by subtituting 0 for 'x'.

$y = \frac{2}{3} (0) -3 = -3$

Now that we found that y-intercept =-3, any lineal function of the type: $y = ax - 3$ will have the same y-intercept. Where 'a' can take all the real values.

Also, any quadratic function of the type: $y=ax^{2} + bx - 3$ will have the same y-intercept. Where 'a' and 'b' can take all the real values.

6 0

3 years ago