A rectangle with an area of 22 - 16.3 + 60 square units could have which possible dimensions?
1 answer:
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Answer:
y= -1/4x + 3
Step-by-step explanation:
y-y1 = m(x-x1)
(-8 {x1}, -5 {y1}, -1/4 [m] )
We'll then replace the letters with the available figures.
y-[-5] = -1/4 (x-[-8])
We are made to know that minus + minus= plus
Minus + plus= Minus
Minus x minus = plus
minus x plus = minus
Therefore, the mathematical setting of this question becomes,
y+5 = -1/4 (x+8)
Multiply everything in the bracket with the outside value
-1/4 x X = -1/4x
-1/4 x 8 = -2
The mathematical setting then becomes,
y+5 = -1/4x + -2 (<em>Note: plus + minus = minus</em>)
so, it becomes
y+5 = -1/4x - 2
The equation is supposed to look like this, y= mx + b
Therefore we add +5 to both sides to cancel out
y+5 = -1/4x - 2
+5 +5
+5 cancels out +5 which makes the setting,
y= -1/4x - 2 +5 (<em>-2+5 goes around to become 5-2= 3</em>)
The expression now looks like this
<u>y= -1/4x +3 which is the final answer!</u>
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