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ludmilkaskok [199]
3 years ago
12

A rectangle with an area of 22 - 16.3 + 60 square units could have which possible dimensions?

Mathematics
1 answer:
Burka [1]3 years ago
8 0

Answer:

wasdwasdwasdwasdadadasdasadwawdawwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwsssssssadwasdwa

Step-by-step explanation:

You might be interested in
Solve for the indicated variable (y) <br> 9x+y=7
Gnesinka [82]
1. Slope=9
2. x-intercept = 7/9 = 0.77778
3. y-intercept = 7/-1= -7.00000
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation: 9*X-Y-(7)=0
Hope this helps
7 0
3 years ago
How do you solve 36 times <img src="https://tex.z-dn.net/?f=%5Csqrt%7B3%7D" id="TexFormula1" title="\sqrt{3}" alt="\sqrt{3}" ali
pantera1 [17]

Answer:

  62.3538

Step-by-step explanation:

There is nothing to solve. If you need a decimal value, you can use a calculator or table of square roots.

8 0
3 years ago
briana house is at (1,6) and jordan house is(5,3) what is one possible path from brianna house to jordan house
Maurinko [17]

Answer:

see the explanation

Step-by-step explanation:

Let

A (1,6)------> location Brianna's house on a map

B (5,3)------> location Jordan's house on a map

we know that

One possible path from Brianna's house to Jordan's house it's a straight line  ( the shortest distance)

using a graph tool

see the attached figure

<em>Find the distance points AB</em>

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

substitute the values

d_A_B=\sqrt{(3-6)^{2}+(5-1)^{2}}

d_A_B=\sqrt{(-3)^{2}+(4)^{2}}

d_A_B=\sqrt{25}

d_A_B=5\ units

The distance from Brianna's house to Jordan's house is 5 units

6 0
3 years ago
Rewrite in simplest terms : <br> 9(-8d - 7 ) +6(d+7)
Pepsi [2]

Answer: -66d-21 I think.

Step-by-step explanation:

9(-8d-7<u>)</u>+6(d+7)

-72d-63+6d+42 Distributive Property

-72d+6d+-63+42 Combine Like Terms

-66d-21 Answer

8 0
2 years ago
Which function has the same y-intercept as the function y equals 2/3 x - 3​
aleksley [76]

We have the function y = \frac{2}{3} x -3 and we want to find a function that has the same y-intercept than the previous function.

First, let's find the y-intercept by subtituting 0 for 'x'.

y = \frac{2}{3} (0) -3 = -3

Now that we found that y-intercept =-3, any lineal function of the type: y = ax - 3 will have the same y-intercept. Where 'a' can take all the real values.

Also, any quadratic function of the type: y=ax^{2} + bx - 3 will have the same y-intercept. Where 'a' and 'b' can take all the real values.

6 0
3 years ago
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