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ludmilkaskok [199]
3 years ago
12

A rectangle with an area of 22 - 16.3 + 60 square units could have which possible dimensions?

Mathematics
1 answer:
Burka [1]3 years ago
8 0

Answer:

wasdwasdwasdwasdadadasdasadwawdawwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwsssssssadwasdwa

Step-by-step explanation:

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Which is the correct answer​
Sav [38]

Answer:

Option 3

Step-by-step explanation:

Using the order of operations, you will find out that 7 x 10^3 = 7,000, and 3 x 10^2 = 300. Dividing 7,000 by 300 will get you 23.333~, so 300 does go into 7,000 a little more than 20 times.

8 0
2 years ago
Alma brought pens of green and blue color. 35% of pens are blue. If she brought a total of 70 pens, how many green pens did she
jeyben [28]

Answer:

24.5% are green

Step-by-step explanation:

7 0
3 years ago
The mean amount purchased by a typical customer at Churchill's Grocery Store is $27.50 with a standard deviation of $7.00. Assum
Schach [20]

Answer:

a) 0.0016 = 0.16% probability that the sample mean is at least $30.00.

b) 0.8794 = 87.94% probability that the sample mean is greater than $26.50 but less than $30.00

c) 90% of sample means will occur between $26.1 and $28.9.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 27.50, \sigma = 7, n = 68, s = \frac{7}{\sqrt{68}} = 0.85

a. What is the likelihood the sample mean is at least $30.00?

This is 1 subtracted by the pvalue of Z when X = 30. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem, we have that:

Z = \frac{X - \mu}{s}

Z = \frac{30 - 27.5}{0.85}

Z = 2.94

Z = 2.94 has a pvalue of 0.9984

1 - 0.9984 = 0.0016

0.0016 = 0.16% probability that the sample mean is at least $30.00.

b. What is the likelihood the sample mean is greater than $26.50 but less than $30.00?

This is the pvalue of Z when X = 30 subtracted by the pvalue of Z when X = 26.50. So

From a, when X = 30, Z has a pvalue of 0.9984

When X = 26.5

Z = \frac{X - \mu}{s}

Z = \frac{26.5 - 27.5}{0.85}

Z = -1.18

Z = -1.18 has a pvalue of 0.1190

0.9984 - 0.1190 = 0.8794

0.8794 = 87.94% probability that the sample mean is greater than $26.50 but less than $30.00.

c. Within what limits will 90 percent of the sample means occur?

Between the 50 - (90/2) = 5th percentile and the 50 + (90/2) = 95th percentile, that is, Z between -1.645 and Z = 1.645

Lower bound:

Z = \frac{X - \mu}{s}

-1.645 = \frac{X - 27.5}{0.85}

X - 27.5 = -1.645*0.85

X = 26.1

Upper Bound:

Z = \frac{X - \mu}{s}

1.645 = \frac{X - 27.5}{0.85}

X - 27.5 = 1.645*0.85

X = 28.9

90% of sample means will occur between $26.1 and $28.9.

4 0
3 years ago
What is The difference of 3 and a number X
slamgirl [31]

Answer:

"the difference of" means to subtract

Therefore, "the difference of 3 and a number" would be:

3-x

Step-by-step explanation:

7 0
3 years ago
A 6 sided number cube is tossed. what is the probability of rolling a 6 or an odd number?
Veronika [31]
For any probability the formula is P_{desired}=\frac{desired}{total}. In this case we have 4 desired outcomes (the odds, 1, 3 and 5, and also 6) out of 6 total sides, so our probability P_{oddor6} =\frac{odd or 6}{total sides}=\frac{4}{6} = \frac{2}{3}.

Mutually exclusive means the events cant occur at the same time. In our case it is not possible to roll both a 6 and an odd number at the same time since 6 is even. Therefore the events ARE mutually exclusive. 

Combine the two parts and C is the correct answer.  <span />
3 0
3 years ago
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