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3 years ago

Solve for the indicated variable (y) 9x+y=7

1 answer:

7 0

1. Slope=9
2. x-intercept = 7/9 = 0.77778
3. y-intercept = 7/-1= -7.00000
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation: 9*X-Y-(7)=0
Hope this helps

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Are these ratios equivalent? 12 friends : 15 strangers AND 6 friends : 14 strangers

meriva

Answer:

Step-by-step explanation:

12:15 can be simplified to 4:5

6:14 can be simplified to 3:7

These two are not equivalent to eachother

6 0

3 years ago

A half-century ago, the mean height of women in a particular country in their 20s was 64.7 inches. Assume that the heights of

Ainat [17]

Answer:

99.5% of all samples of 21 of today's women in their 20's have mean heights of at least 65.86 inches.

Step-by-step explanation:

We are given that a half-century ago, the mean height of women in a particular country in their 20's was 64.7 inches. Assume that the heights of today's women in their 20's are approximately normally distributed with a standard deviation of 2.07 inches.

Also, a samples of 21 of today's women in their 20's have been taken.

Let $\bar X$ = sample mean heights

The z-score probability distribution for sample mean is given by;

Z = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean height of women = 64.7 inches

$\sigma$ = standard deviation = 2.07 inches

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the sample of 21 of today's women in their 20's have mean heights of at least 65.86 inches is given by = P( $\bar X$ $\geq$ 65.86 inches)

P( $\bar X$ $\geq$ 65.86 inches) = P( $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ $\geq$ $\frac{65.86-64.7}{\frac{2.07}{\sqrt{21} } }$ ) = P(Z $\geq$ -2.57) = P(Z $\leq$ 2.57)

= 0.99492 or 99.5%

The above probability is calculated by looking at the value of x = 2.57 in the z table which has an area of 0.99492.

Therefore, 99.5% of all samples of 21 of today's women in their 20's have mean heights of at least 65.86 inches.

3 0

3 years ago

Can someone help me with this i am confused

Eva8 [605]

Plot each point on a graph , then count how many you need to go up and then over in this case it is 8 over 1 then calculate the y int so y= 8x -25

6 0

3 years ago

-4(x+1)+5=17 solve for x

ahrayia [7]

-4(x + 1) + 5 = 17

Distribute -4 inside the parentheses.

(-4x - 4) + 5 = 17

Combine like terms (-4 + 5).

-4x + 1 = 17

Subtract 1 from both sides.

-4x = 16

Divide both sides by -4.

x = -4

3 0

3 years ago

Read 2 more answers

Michelle opened a savings account for her emergency fund. She deposited $2,000 into her account, which earns 2.10% interest, com

mrs_skeptik [129]

Answer: she will have $2042.4 have in the account after 1 year.

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1 + r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = $2000

r = 2.1% = 2.1/100 = 0.021

n = 12 because it was compounded 12 times in a year.

t = 1 year

Therefore,

A = 2000(1 + 0.021/12)^12 × 1

A = 2000(1 + 0.00175)^12

A = 2000(1.00175)^12

A = $2042.4

5 0

3 years ago