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luda_lava [24]
3 years ago
8

Cost equation Y=10x + 15 Y=25x + 8 At what point does these cost the same.

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
4 0

Answer:

x=7/15

Step-by-step explanation:

I'm not sure what x means but if you solve the equation it is 7/15

First you would set 10x+15 equal to 25x+8 which would look like 10x+15=25x+8

Then you would combine like terms by subtracting 8 from both sides to get 10x+7=25x

Then subtract 10x from both sides and get 7=15x

So then to get x by itself you would divide both sides by 15 and get 7/15=x

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\bf sin(\theta )=\cfrac{\stackrel{opposite}{2~~\begin{matrix} x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }}{\stackrel{hypotenuse}{~~\begin{matrix} x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ \sqrt{5}}}\implies \stackrel{\textit{and rationalizing the denominator}~\hfill }{\cfrac{2}{\sqrt{5}}\cdot \cfrac{\sqrt{5}}{\sqrt{5}}\implies \cfrac{2\sqrt{5}}{(\sqrt{5})^2}\implies \cfrac{2\sqrt{5}}{5}}

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