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luda_lava [24]
3 years ago
8

Cost equation Y=10x + 15 Y=25x + 8 At what point does these cost the same.

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
4 0

Answer:

x=7/15

Step-by-step explanation:

I'm not sure what x means but if you solve the equation it is 7/15

First you would set 10x+15 equal to 25x+8 which would look like 10x+15=25x+8

Then you would combine like terms by subtracting 8 from both sides to get 10x+7=25x

Then subtract 10x from both sides and get 7=15x

So then to get x by itself you would divide both sides by 15 and get 7/15=x

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Jackson says has an odd number of model cars.he has 6 cars on one shel and 8 cars on another shelf.is jackson correct?explain
grigory [225]
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I hope this helps! If not I'm sorry. 
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3 years ago
Which pair of expressions represents inverse functions
Natali5045456 [20]

Answer: C. \dfrac{x+3}{4x-2} and \dfrac{2x+3}{4x-1}


Step-by-step explanation: if a function f(x) has g(x) as its inverse then it satisfies fog(x)=x and gof(x)=x

C. f(x)=\dfrac{x+3}{4x-2} and g(x)=\dfrac{2x+3}{4x-1}

   fog(x)=f(\dfrac{2x+3}{4x-1})

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               =x

   gof(x)=g(\dfrac{x+3}{4x-2})

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7 0
3 years ago
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WILL GIVE BRAINLIEST&amp; 15 PTS.
kicyunya [14]

Answer:

The given fraction \frac{x^3-x^2}{x^3} reduces to  \frac{x-1}{x}

Step-by-step explanation:

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We have to reduce the fraction to the lowest terms.

Consider numerator x^3-x^2

We can take x² common from both the term,

Thus, numerator can be written as x^2(x-1)

Given expression can be rewritten as ,

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We can now cancel x^2 from both numerator and denominator,

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\Rightarrow \frac{(x-1)}{x^2 \cdot x}=\frac{x-1}{x}

Thus, the given fraction \frac{x^3-x^2}{x^3} reduces to  \frac{x-1}{x}

6 0
3 years ago
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Anuta_ua [19.1K]

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5 0
3 years ago
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