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vfiekz [6]
3 years ago
6

Gibson family have bought tickets to the christmas market there are four mothers, 2 grandmothers and 4 daughters what is the min

imum number of tickets they need
Mathematics
1 answer:
djverab [1.8K]3 years ago
8 0
We have six ladies and name them:

1,2,3,4,5,6

where 5 and 6 are the daughters of 3 and 4, 3 and 4 are daughters of 1 and 2.

Now,
1 and 2 are mothers of 3 and 4 = 2 mothers
3 and 4 are mothers of 5 and 6 = 2 mothers
1 and 2 are the grandmothers of 5 and 6 = 2 grandmothers
5 and 6 are the daughters of 3 and 4 = 2 daughters
3 and 4 are the daughters of 1 and 2 = 2 daughters
2 granddaughters 5 and 6

So now you have a list of 12 people ! ... 4 mothers, 2 grandmothers, 
4 daughters, and 2 grand-daughters ... and they all get in to the Christmas Market with only six tickets.  
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a string is 14.9 meters long and needs to be cut into smaller pieces of 0.52 meter each. what is the greatest number of pieces y
alex41 [277]

Answer:

28 pieces

Step-by-step explanation:

14.9 ÷ 0.52 = 28.653

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2 years ago
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Consider this right triangle.<br> 21<br> 29<br> 20<br> Enter the ratio equivalent to s
AleksAgata [21]

Answer:

Part 1) sin(B)=\frac{21}{29}

Part 2) csc(A)=\frac{29}{20}

Part 3) cot(A)=\frac{21}{20}

Step-by-step explanation:

<u><em>The complete question is</em></u>

Consider this right triangle. 21 29 20 Write the ratio equivalent to: Sin B - CscA- Cot B

The picture of the question in the attached figure

Part 1) Write the ratio equivalent to: Sin B

we know that

In the right triangle ABC

sin(B)=\frac{AC}{AB} ----> by SOH (opposite side divided by the hypotenuse)

substitute the values

sin(B)=\frac{21}{29}

Part 2) Write the ratio equivalent to: Csc A

we know that

In the right triangle ABC

csc(A)=\frac{1}{sin(A)}

sin(A)=\frac{BC}{AB} -----> by SOH (opposite side divided by the hypotenuse)

substitute the values

sin(A)=\frac{20}{29}

therefore

csc(A)=\frac{29}{20}

Part 3) Write the ratio equivalent to: Cot A

we know that

In the right triangle ABC

cot(A)=\frac{1}{tan(A)}

tan(A)=\frac{BC}{AC} -----> by TOA (opposite side divided by the adjacent side)

substitute the values

tan(A)=\frac{20}{21}

therefore

cot(A)=\frac{21}{20}

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AysviL [449]

Answer:

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Step-by-step explanation:

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2 years ago
Please answer this question now
Rashid [163]

Answer:

54

Step-by-step explanation:

To solve problems like this, always recall the "Two-Tangent theorem", which states that two tangents of a circle are congruent if they meet at an external point outside the circle.

The perimeter of the given triangle = IK + KM + MI

IK = IJ + JK = 13

KM = KL + LM = ?

MI = MN + NI ?

Let's find the length of each tangents.

NI = IJ = 5 (tangents from external point I)

JK = IK - IJ = 13 - 5 = 8

JK = KL = 8 (Tangents from external point K)

LM = MN = 14 (Tangents from external point M)

Thus,

IK = IJ + JK = 5 + 8 = 13

KM = KL + LM = 8 + 14 = 22

MI = MN + NI = 14 + 5 = 19

Perimeter = IK + KM + MI = 13 + 22 + 19 = 54

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Answer:

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Step-by-step explanation:

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