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zmey [24]
3 years ago
8

Help?(i suck at math)

Mathematics
2 answers:
Katena32 [7]3 years ago
6 0
The answer would be 4/3
FinnZ [79.3K]3 years ago
5 0

Answer:

7 is the answer add 3 and 4 to gather

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Can the sum or multiplication of two palindromic numbers be another palindromic number?​
rosijanka [135]

Answer: No.

Step-by-step explanation:

If you multiply 1001 by 1001 it's not another palindromic number.

6 0
2 years ago
Jeff left 4/5 of the pumpkin pie in the refrigerator on Saturday he ate 1/2 if what was left of the pie what fraction of the ent
sukhopar [10]
He ate 2/5 of the pie on Saturday.
7 0
3 years ago
A prticular type of tennis racket comes in a midsize versionand an oversize version. sixty percent of all customers at acertain
svetlana [45]

Answer:

a) P(x≥6)=0.633

b) P(4≤x≤8)=0.8989 (one standard deviation from the mean).

c) P(x≤7)=0.8328

Step-by-step explanation:

a) We can model this a binomial experiment. The probability of success p is the proportion of customers that prefer the oversize version (p=0.60).

The number of trials is n=10, as they select 10 randomly customers.

We have to calculate the probability that at least 6 out of 10 prefer the oversize version.

This can be calculated using the binomial expression:

P(x\geq6)=\sum_{k=6}^{10}P(k)=P(6)+P(7)+P(8)+P(9)+P(10)\\\\\\P(x=6) = \binom{10}{6} p^{6}q^{4}=210*0.0467*0.0256=0.2508\\\\P(x=7) = \binom{10}{7} p^{7}q^{3}=120*0.028*0.064=0.215\\\\P(x=8) = \binom{10}{8} p^{8}q^{2}=45*0.0168*0.16=0.1209\\\\P(x=9) = \binom{10}{9} p^{9}q^{1}=10*0.0101*0.4=0.0403\\\\P(x=10) = \binom{10}{10} p^{10}q^{0}=1*0.006*1=0.006\\\\\\P(x\geq6)=0.2508+0.215+0.1209+0.0403+0.006=0.633

b) We first have to calculate the standard deviation from the mean of the binomial distribution. This is expressed as:

\sigma=\sqrt{np(1-p)}=\sqrt{10*0.6*0.4}=\sqrt{2.4}=1.55

The mean of this distribution is:

\mu=np=10*0.6=6

As this is a discrete distribution, we have to use integer values for the random variable. We will approximate both values for the bound of the interval.

LL=\mu-\sigma=6-1.55=4.45\approx4\\\\UL=\mu+\sigma=6+1.55=7.55\approx8

The probability of having between 4 and 8 customers choosing the oversize version is:

P(4\leq x\leq 8)=\sum_{k=4}^8P(k)=P(4)+P(5)+P(6)+P(7)+P(8)\\\\\\P(x=4) = \binom{10}{4} p^{4}q^{6}=210*0.1296*0.0041=0.1115\\\\P(x=5) = \binom{10}{5} p^{5}q^{5}=252*0.0778*0.0102=0.2007\\\\P(x=6) = \binom{10}{6} p^{6}q^{4}=210*0.0467*0.0256=0.2508\\\\P(x=7) = \binom{10}{7} p^{7}q^{3}=120*0.028*0.064=0.215\\\\P(x=8) = \binom{10}{8} p^{8}q^{2}=45*0.0168*0.16=0.1209\\\\\\P(4\leq x\leq 8)=0.1115+0.2007+0.2508+0.215+0.1209=0.8989

c. The probability that all of the next ten customers who want this racket can get the version they want from current stock means that at most 7 customers pick the oversize version.

Then, we have to calculate P(x≤7). We will, for simplicity, calculate this probability substracting P(x>7) from 1.

P(x\leq7)=1-\sum_{k=8}^{10}P(k)=1-(P(8)+P(9)+P(10))\\\\\\P(x=8) = \binom{10}{8} p^{8}q^{2}=45*0.0168*0.16=0.1209\\\\P(x=9) = \binom{10}{9} p^{9}q^{1}=10*0.0101*0.4=0.0403\\\\P(x=10) = \binom{10}{10} p^{10}q^{0}=1*0.006*1=0.006\\\\\\P(x\leq 7)=1-(0.1209+0.0403+0.006)=1-0.1672=0.8328

7 0
3 years ago
If you spend $8 dollars every school day on fast food. How much money would you spend in 1 school year
Nadya [2.5K]
8 * 5 = 40

40 * 4 = 160

160 * 12 = 1,920

Answer: $1,920
6 0
3 years ago
Read 2 more answers
A candle burned at a steady rate. After 33 minutes, the candle was 11.2 inches tall. Eighteen minutes later, it was 10.75 inches
Amiraneli [1.4K]

Answer:

9.025 inches

Step-by-step explanation:

Let the length be represented by:

L = mt+L_0

Where L is the length of candle at time t

m is the rate at which the candle is burning.

And L_0 is the initial length of the candle.

As per the question statement, let us put the given values in the equation.

11.2 = m\times 33 + L_0 .... (1)\\10.75 = m\times 51+L_0 ..... (2)

Subtracting (1) from (2):

0.45 = -18m\\\Rightarrow m = -0.025

Putting the value of m in the equation (1):

11.2 = -0.025 \times 33+L_0\\\Rightarrow L_0 = 12.025

Therefore, the equation becomes:

L = -0.025t + 12.025

Now, we have to find the height of candle after 2 hours.

2 hours mean 120 minutes.

L = -0.025 \times 120 + 12.025\\\Rightarrow L = 9.025\ inches

Therefore, the height of candle is <em>9.025 inches</em>.

3 0
2 years ago
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