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3 years ago

When using a quadratic equation of the form ax2 +bx+c=0 to find a distance what should be "ignored"

1 answer:

3 0

You should ignore the negative answers because you can't have negative distance. For example, if you are going back 7 feet, you are still going 7 feet. In that situation, the answer would 7 not -7.

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Two friends are renting an apartment. They pay the landlord the first month’s rent. The landlord also requires them to pay an ad

UNO [17]

So you could do $1725/3 (divided by) which would give you 575 then mulitply that by two and that will give you the months rent of, $1,150. I hope this helps!

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3 years ago

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Please don’t answer this im testing something

prisoha [69]

Answer:

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Step-by-step explanation:

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the area of a rectangle city park is 25/54 sqaure miles. the length of the park is 5/9 mile. what is the width in miles of the p

andreyandreev [35.5K]

A = lw

Plug in what we know:

25/54 = (5/9)w

Divide 5/9 to both sides or multiply by its reciprocal, 9/5:

25/54 * 9/5 = w

Multiply the numerators and denominators together:

225/270 = w

Simplify:

<span>w = 5/6</span>

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3 years ago

Liberty bought a make-your-own salad when she went out to lunch at a restaurant. The salad cost $4, plus $0.85 for each salad to

Bogdan [553]

I believe you answer would be $4 + $0.85t =$9.95

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3 years ago

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Triangle PQR has vertices , , and . It is translated according to the rule . What is the y-value of ?

steposvetlana [31]

Answer:

-10 is the correct answer to the given question .

Step-by-step explanation:

Missing information:

Following question is incomplete there is no information about the vertices and the rules .Following are the complete question that is mention below

Triangle PQR has vertices $P(-2, 6), \ Q(-8, 4), and\ R(1, -2).$ It is translated according to the rule $(x, y)\ -> \ (x\ - \ 2, y\ - 16)$ . What is the y-value of P'?

Now coming to the solution as already mention in the question

The translated rule is $(x, y)\ -> (x - 2, \ y -16).$

Now calculated the vertices P value according to the rule of translated

$P(-2, 6)\\Now \ apply \ the\ translated\ rule \ in\ P\ vertices\\P(-2, 6)->P1(-2-2,\ 6-16)\\P1->(-4,-10)$

So -10 is the value of y in P vertices .

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3 years ago

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