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2 years ago

Maggie needs to spend at least six hours each week practicing the piano. She has already practiced 3

Mathematics

1 answer:

grandymaker [24]2 years ago

8 0

Answer:

t ≥ 1.5

Step-by-step explanation:

Lets take time for practicing the piano to be t

The number of hours to practice per week should be at least 6 hours

This is written as t ≥ 6

She already practiced 3 hours this week, thus the remaining hours to practice should be

t ≥ 3

The minimum remaining hours to practice for the remaining 2 days should be

t=3

If these hours are evenly divided, then in a single day she should practice

for t ≥ 1.5

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Which sum or difference identity would you use to verify that cos (180° - q) = -cos q?

Phantasy [73]

Answer:

$\cos (a-b)=\cos a \cos b+\sin a \sin b$

Step-by-step explanation:

Given : $\cos (180^{\circ}-q)=-\cos q$

We have to write which identity we will use to prove the given statement.

Consider $\cos (180^{\circ}-q)=-\cos q$

Take left hand side of given expression $\cos (180^{\circ}-q)$

We know

$\cos (a-b)=\cos a \cos b+\sin a \sin b$

Comparing , we get, a= 180° and b = q

Substitute , we get,

$\cos (180^{\circ}-q)=\cos 180^{\circ} \cos (q)+\sin q \sin 180^{\circ}$

Also, we know $\sin 180^{\circ}=0$ and $\cos 180^{\circ}=-1$

Substitute, we get,

$\cos (180^{\circ}-q)=-1\cdot \cos (q)+\sin q \cdot 0$

Simplify , we get,

$\cos (180^{\circ}-q)=-\cos (q)$

Hence, use difference identity to prove the given result.

7 0

3 years ago

Read 2 more answers

Sophie [7]

Answer:

Step-by-step explanation:

I graphed it but you could also use the y intercept to determine which function matches the graph

log(x+1)<u>+3</u>

the +3 at the end of the function makes the y-intercept positive 3

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2 years ago

7x^2+66xy+80y^2 Please help me out i need this answer

lilavasa [31]

<span>There are no like terms.

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2 years ago

Researchers have noted a decline in cognitive functioning as people age (Bartus, 1990). However, the results from other research

kolbaska11 [484]

Complete Question

The complete question is shown on the first uploaded image

Answer:

Yes the researcher can conclude that the supplement has a significant effect on cognitive skill

$d = 0.5778$

The result of this hypothesis test shows that there is sufficient evidence to that the supplement had significant effect.The measure of effect size is large due to the large value of Cohen's d (0.5778 > 0.30 )

Step-by-step explanation:

From the question we are told that

The sample size is n=16

The sample mean is $M = 50.2$

The standard deviation is $\sigma = 9$

The population mean is $\mu = 45$

The level of significance is $\alpha = 0.05$

The null hypothesis is $H_o \mu =45$

The alternative hypothesis is $H_a \mu \ne 45$

Generally the test statistics is mathematically represented as

$z = \frac{M - \mu}{\frac{\sigma}{\sqrt{n} } }$

=> $z = \frac{50.2 - 45}{\frac{9}{\sqrt{16} } }$

=> $z = 2.31$

Generally the p-value is mathematically represented as

$p-value = 2 * P(Z > z )$

$p-value = 2 * P(Z > 2.31 )$

From the z-table

$P(Z > 2.31 ) = 0.010444$

=> $p-value = 2 * 0.010444$

=> $p-value = 0.021$

From the obtained values we see that $p-value < 0.05$

Decision Rule

Reject the null hypothesis

Conclusion

There is sufficient evidence to conclude that the supplement has a significant effect on the cognitive skill of elderly adults

Generally the Cohen's d for this study is mathematically represented as

$d = \frac{M - \mu}{\sigma }$

=> $d = \frac{50.2 -45}{9 }$

=> $d = 0.5778$

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3 years ago

The value of 9 in 495,123 is blank times the value of 9 in 63,129

mafiozo [28]

The answer is 90,000.
The value of 9 in 495,123 is 10,000 times the value of 9 in 63,129

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2 years ago