- 5 1/4 <span>÷ 2 3/4 =
= - 21/4 </span><span>÷ 11/4
= - 21/4 * 4/11
= - 21/11
= - 1 10/11
</span>
) Using formula for cicumference.
Circumference = Pi * diameter
Circumference = Pi * 80m
Circumference = 251.2m.
Total inside length of the curved ends.
2)Total distance round inside of track =
2(125) + 251.2m
= 250 + 251.2
= 501.2m
3) Area of circular ends =
Pi*r^2
= Pi*40^2
= 5024m^2
Area of central area (rectangle)
length * width
125m * 80m
= 10,000m^2
Total area inside track =
5,024m^2 + 10,000m^2
= 15,024m^2
Hope this helps.
:-)
Answer: 
Step-by-step explanation:
For this exercise you need to use the Inverse Trigonometric function arcsine, which is defined as the inverse function of the sine.
Then, to find an angle α, this is:
In this case, you can identify that:
Then, substituting values into and evaluating, you get that the measure of the angle "C" to the nearest degree, is:
3x + 5y = 1 . . . . . . . . (1)
7x + 4y = -13 . . . . . . .(2)
(1) x 7: 21x + 35y = 7 . . (3)
(2) x 3: 21x + 12y = -39 .(4)
(3) - (4) = 23y = 46
y = 46/23 = 2
1km is 1000 m
1000m+125m-375m=750m
