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3 years ago

Describe the end behavior of the graph

Mathematics

1 answer:

USPshnik [31]3 years ago

6 0

Answer:

Option C, f(x) -> +∞ as x -> -∞ and f(x) -> -∞ as x -> +∞

Step-by-step explanation:

Since as x goes to negative infinity the y value goes to positive infinity:

f(x) -> +∞ as x -> -∞

Since as x goes to infinity the y value goes to negative infinity:

f(x) -> -∞ as x -> +∞

Answer: Option C, f(x) -> +∞ as x -> -∞ and f(x) -> -∞ as x -> +∞

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I need help with this algebra 2 question, please dont answer if you dont know

Illusion [34]

Answer:

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Step-by-step explanation:

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3 years ago

i kind of know its C need 2nd opinion A tire manufacturer took a random sample of 50 tires and found that 3 were defective. In a

den301095 [7]

It's kind of not C.

Solve this proportion for 'x':

3/50 = x/2400

Hint: Cross-multiply the proportion, then do what you need to do.

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3 years ago

Is 0.06 bigger than 1?

taurus [48]

Hi there!

Great question! 0.06 is actually SMALLER than 1.

Why?

Because 0.06 is almost half of the whole number. Half of 1 is 0.5, which is larger than 0.06.

Half is smaller than whole, so, therefore, 1 is larger.

Hope this helps!

Message me if you need anything else! I'd be happy to help! :D

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3 years ago

Read 2 more answers

How can the x-intercept and y-intercept be used to graph a linear equation

JulijaS [17]

Because a line always goes past the y-intercept and x-intercept. It's not always both, it can sometimes just be the x-intercept or the y-intercept.

When a line intersects these points, for example if a line was to intersect the x-axis then y would be equal to 0, and the opposite for the y-axis. If a line was to intersect the y-axis x would be equal to 0.

Therefore by using that knowledge, and the equation of the line [ y=mx+c or y-y1=m(x-x1) ], we can find the equation of our line. Of course you would need the gradient of that line (the value "m").

5 0

3 years ago

A professor pays 25 cents for each blackboard error made in lecture to the student who pointsout the error. In a career ofnyears

marta [7]

Answer:

(a) The probability that Y₂₀ exceeds 1000 is 3.91 × 10⁻⁶.

(b) n = 28.09

Step-by-step explanation:

The random variable Yₙ is defined as the total numbers of dollars paid in n years.

It is provided that Yₙ can be approximated by a Gaussian distribution, also known as Normal distribution.

The mean and standard deviation of Yₙ are:

$\mu_{Y_{n}}=40n\\\sigma_{Y_{n}}=\sqrt{100n}$

(a)

For n = 20 the mean and standard deviation of Y₂₀ are:

$\mu_{Y_{n}}=40n=40\times20=800\\\sigma_{Y_{n}}=\sqrt{100n}=\sqrt{100\times20}=44.72\\$

Compute the probability that Y₂₀ exceeds 1000 as follows:

$P(Y_{n}>1000)=P(\frac{Y_{n}-\mu_{Y_{n}}}{\sigma_{Y_{n}}}>\frac{1000-800}{44.72})\\=P(Z> 4.47)\\=1-P(Z$

**Use a z table for probability.

Thus, the probability that Y₂₀ exceeds 1000 is 3.91 × 10⁻⁶.

(b)

It is provided that P (Yₙ > 1000) > 0.99.

$P(Y_{n}>1000)=0.99\\1-P(Y_{n}$

The value of z for which P (Z < z) = 0.01 is 2.33.

Compute the value of n as follows:

$z=\frac{Y_{n}-\mu_{Y_{n}}}{\sigma_{Y_{n}}}\\2.33=\frac{1000-40n}{\sqrt{100n}}\\2.33=\frac{100}{\sqrt{n}}-4\sqrt{n} \\2.33=\frac{100-4n}{\sqrt{n}} \\5.4289=\frac{(100-4n)^{2}}{n}\\5.4289=\frac{10000+16n^{2}-800n}{n}\\5.4289n=10000+16n^{2}-800n\\16n^{2}-805.4289n+10000=0$

The last equation is a quadratic equation.

The roots of a quadratic equation are:

$n=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$

a = 16

b = -805.4289

c = 10000

On solving the last equation the value of n = 28.09.

8 0

3 years ago