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MArishka [77]
3 years ago
12

Evaluate the expression |2x-8| X=2

Mathematics
2 answers:
Julli [10]3 years ago
6 0

Answer:

4

Step-by-step explanation:

masha68 [24]3 years ago
3 0

Answer:

4

Step-by-step explanation:

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jek_recluse [69]
What the heckk??????????
6 0
3 years ago
In order for the parallelogram to be a rhombus x = ?
Zina [86]

Answer: x= 207.8873386

Step-by-step explanation:

expecting both 2x-15 and 3x are angles in radiant, let's draw a rhombus ABCD

∠ABC = 2x-15

∠ BCD = 3x

∠ABC + < BCD= π ( 180° in radiant)

2x - 15 + 3x = π

5x - 15 = π

x - 3 = 1/5π

= 3.628318531 = 207.8873386

2x−15°+3x=180

5x-15°=180

5x=195°

x=39°

7 0
3 years ago
There are (49)5 • 40 books at the library. What is the total number of books at the library? (4 points)
madreJ [45]
5 times 40 times 49 equals 9800 because you do 5 time 4 and that's 20 and you add a 0 and you multiply by 49 to get 9800.
5 0
3 years ago
Read 2 more answers
Based on the information below, choose the correct answers. Note: The monthly loan payment was calculated at 119 payments of $33
Margaret [11]

Answer:

  • $122.04
  • 36.94%

Step-by-step explanation:

a) The amount of concern is ...

  (total interest)/(number of payments) = interest/payment

  $14,644.95/120 ≈ $122.04 . . . . amount of interest per payment

__

b) The ratio of concern is ...

  (total interest)/(total payments) × 100% = 14,644.95/39,644.95 × 100%

  ≈ 36.94% . . . . percent of total payments that is interest

6 0
3 years ago
a sample of 546 boys aged 6–11 was weighed, and it was determined that 89 of them were overweight. A sample of 508 girls aged 6–
AleksAgata [21]

Answer:

p-value:  0.6527

Step-by-step explanation:

Hello!

You have two samples to study, from each sample the weight of each child was measured and counted the total of overweight kids (x: "success") in each group:

Sample 1 (Boys aged 6-11)

n₁= 546

x₁= 89

^p₁= x₁/n₁ = 89/546 ≅0.16

Sample 2 (girls aged 6-11)

n=508

x= 74

^p= x/n = 74/508 ≅ 0.15

If the hypothesis statement is "The proportion of boys that are overweight differs from the proportion of girls that are overweight", the test hypothesis is:

H₀: ρ₁ = ρ₂

H₁: ρ₁ ≠ ρ₂

This type of hypothesis leads to a two-tailed rejection region, then the p-value will also be two-tailed. To calculate the p-value you have to first calculate the value of the statistic under the null hypothesis, in this case, is a test for the difference between two proportions:

Z=<u>      (^ρ₁ - ^ρ₂) - (ρ₁ - ρ₂)        </u> ≈ N(0;1)

    √(ρ` * (1 - ρ`) * (1/n₁ + 1/n₂))

ρ`=<u> x₁ + x₂  </u> = <u>  89+74     </u> = 0.154 ≅ 0.15

     n₁ + n₂     546 + 508

Z⁰ᵇ =<u>          (0.16-0.15) - (0)                    </u>

       √(0.15 * (1 - 0.15) * (1/546 + 1/508))

Z⁰ᵇ = 0.45

I've mentioned before that in this test you have a two-tailed p-value. The value calculated (0.45) corresponds to the right or positive tail and the left tail is symmetrical to it concerning the distribution mean, in this case, is 0, so it is -0.45. To obtain the p-value you need to calculate the probability of both values and add them:

P(Z>0.45) + P(Z<-0.45) = (1- P(Z<0.45)) + P(Z<-0.45) = (1-0.67364) + 0.32636 = 0.65272 ≅ 0.6527

p-value:  0.6527

Since there is no signification level in the problem, I'll use the most common to reach a decision. α: 0.05

Since the p-value is greater than α, you do not reject the null Hypothesis, in other words, there is no significative difference between the proportion of overweight boys and the proportion of overweight girls.

I hope it helps!

3 0
3 years ago
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