1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kolezko [41]
3 years ago
6

SOMEONE PLEASE JUST ANSWER THIS FOR BRAINLIEST!!!

Mathematics
1 answer:
stiv31 [10]3 years ago
6 0

ANSWER

a=-2, b=3

EXPLANATION

The given equation is

(a {x}^{2})( - 6 {x}^{b}  ) = 12 {x}^{5}

Recall that:

{a}^{m}  \times  {a}^{n}  =  {a}^{m + n}

We simplify the left hand side to get:

- 6a {x}^{2 + b}  = 12 {x}^{5}

For this equation to be true, we must have:

-6a=12 and 2+b=5

This implies that,

a=-2 and b=3

You might be interested in
Use the graph to describe the rule, write the ordered pairs of the image.
maks197457 [2]

Step-by-step explanation:

Both are translations,

1.) Translation of (5,7)

2.) Translation of (8, -3)

3 0
2 years ago
I really had some trouble with this problem:( & I need some help
Natasha_Volkova [10]
The answers are in the photo

7 0
1 year ago
According to data from a medical​ association, the rate of change in the number of hospital outpatient​ visits, in​ millions, in
GaryK [48]

Answer:

a) f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000

b) f(t=2015) = 264,034,317.7

Step-by-step explanation:

The rate of change in the number of hospital outpatient​ visits, in​ millions, is given by:

f'(t)=0.001155t(t-1980)^{0.5}

a) To find the function f(t) you integrate f(t):

\int \frac{df(t)}{dt}dt=f(t)=\int [0.001155t(t-1980)^{0.5}]dt

To solve the integral you use:

\int udv=uv-\int vdu\\\\u=t\\\\du=dt\\\\dv=(t-1980)^{1/2}dt\\\\v=\frac{2}{3}(t-1980)^{3/2}

Next, you replace in the integral:

\int t(t-1980)^{1/2}=t(\frac{2}{3}(t-1980)^{3/2})- \frac{2}{3}\int(t-1980)^{3/2}dt\\\\= \frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}+C

Then, the function f(t) is:

f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+C'

The value of C' is deduced by the information of the exercise. For t=0 there were 264,034,000 outpatient​ visits.

Hence C' = 264,034,000

The function is:

f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000

b) For t = 2015 you have:

f(t=2015)=0.001155[\frac{2}{3}(2015)(2015-1980)^{1/2}-\frac{4}{15}(2015-1980)^{5/2}]+264,034,000\\\\f(t=2015)=264,034,317.7

3 0
3 years ago
Need help please help me if you know it
scoundrel [369]

Answer:

I believe it's C... Not sure though...

7 0
2 years ago
Help me please please help with is!
frozen [14]
The answer for the question is 21
7 0
3 years ago
Read 2 more answers
Other questions:
  • What is DE ?<br> Please write answer as a decimal
    7·1 answer
  • An Equation is shown.<br><br> 8/10 + ___ = 93/100<br><br> What is the missing fraction?
    7·2 answers
  • Solve for x<br><br> 6x + 3 - 1/2 x = -2x +5
    6·1 answer
  • What are the coordinates of the x-intercepts of the graph of y = 2x2 + 6x – 20? A) (–5, 0) , (2, 0) . B) (5, 0) , (–2, 0) . C) (
    13·1 answer
  • ASAP PLEASEEEEEEEE
    5·1 answer
  • Which is the same as dividing a number by 10?
    13·2 answers
  • How many solutions does the system of equations below have?
    7·2 answers
  • Which equation can be used to determine the value of x?​
    7·2 answers
  • Jeffrey can jog 5 miles in 40 minutes. How many more miles can he jog in 90 minutes than in 40 minutes? Assume the relationship
    9·1 answer
  • What is the domain of the following function: y=x^-5 + (x-1)
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!