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3 years ago

NEED ANSWER PLZ QUICK

Mathematics

2 answers:

Maksim231197 [3]3 years ago

7 0

Hello,

2n - 4 = -12

2n = (-12) + 4 = (-8)

n = (-8) / 2 = (-4)

The correct answer is D.

Bye :)

Troyanec [42]3 years ago

6 0

2n-4=-12

Add 4 to both sides

2n=-8

Divide by 2 on both sides

n=-4

To do these types of questions do reverse PEMDAS. Do the opposite sign such as adding to undo subtraction.

Read more at below link:

brainly.com/question/16878090

#SPJ10

3 0

2 years ago

URGENT!!!!!! PLEASE ANSWER !!!!!!

pochemuha

Answer:

The equation is 18h=378

h=21

Step-by-step explanation:

So first you have to set up the equation

so if she makes 18 dollars an hour the first part of the equation would be 18h

She made 378 dollars in one week so now the equation is 18h=378

The answer is h=21 because 378/18 is 21

4 0

3 years ago

4/5 of a number is 32

andrew11 [14]

Answer:

x = 40

Step-by-step explanation:

Step 1: Write out an equation

4/5(x) = 32

Step 2: Solve by dividing both sides by 4/5

x = 32/(4/5)

<em>Use KCF (Keep Change Flip) if you do not have a calc.</em>

x = 40

6 0

3 years ago

Read 2 more answers

What is the value of 10*100^7/1000^6

skelet666 [1.2K]

Answer:

1000

Step-by-step explanation:

10 x 100 = 1000. 1000^7 / 1000^6 = 1000^1... 1000 to the 1st power is itself.

3 0

3 years ago

Read 2 more answers

30 POINTS AVAILABLE

kherson [118]

Answer:

$\large\boxed{(x-2)^2+(y-1)^2=34}$

Step-by-step explanation:

The equation of a circle in standard form:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the endpoints of the diameter: (-1, 6) and (5, -4).

Midpoint of diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$h=\dfrac{-1+5}{2}=\dfrac{4}{2}=2\\\\k=\dfrac{6+(-4)}{2}=\dfrac{2}{2}=1$

The center is in (2, 1).

The radius length is equal to the distance between the center of the circle and the endpoint of the diameter.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the coordinates of the points (2, 1) and (5, -4):

$r=\sqrt{(5-2)^2+(-4-1)^2}=\sqrt{3^2+(-5)^2}=\sqrt{9+25}=\sqrt{34}$

Finally we have:

$(x-2)^2+(y-1)^2=(\sqrt{34})^2$

3 0

3 years ago