All categories

2 years ago

NEED ANSWER PLZ QUICK

Mathematics

2 answers:

Maksim231197 [3]2 years ago

7 0

Hello,

2n - 4 = -12

2n = (-12) + 4 = (-8)

n = (-8) / 2 = (-4)

The correct answer is D.

Bye :)

Troyanec [42]2 years ago

6 0

2n-4=-12

Add 4 to both sides

2n=-8

Divide by 2 on both sides

n=-4

To do these types of questions do reverse PEMDAS. Do the opposite sign such as adding to undo subtraction.

You might be interested in

If two lines have the same slope and y-intercept, what is true of the lines? A. The lines are perpendicular. B. The lines inters

anyanavicka [17]

D. the lines are the same.

8 0

3 years ago

Read 2 more answers

Change 3 radians to degree measures

uysha [10]

<span>π radians =180∘</span>

1 radian = tex] \frac{180°}{ \pi} [/tex]π

3 radians = $\frac{540°}{ \pi}$

7 0

3 years ago

Read 2 more answers

PLEASE HELP <br> WILL GIVE BRAINLIEST AND 5.0 RATING

jasenka [17]

Answer:

Step-by-step explanation:

(-4,-5)

move up 3 units

change in y-axis

-5+3=-2

(-4,-2)

4 0

2 years ago

Can anyone help me out? I’ll give Brainly! Thank you :)

Oliga [24]

Answer:

The rate of return is 14%

Step-by-step explanation:

The rate of return can be determined by,

RR = $\frac{A_{f} - A_{i} }{A_{i} }$ x 100%

where:

RR is the rate of return

$A_f}$ is the final amount = $690 - $6 = $684

$A_{i}$ is the initial amount = $15 x 40 = $ 600

So that,

RR = $\frac{684 - 600}{600}$ x 100%

= 0.14 x 100%

= 14%

Therefore, the rate of return is 14%.

7 0

2 years ago

The distribution of IQ scores can be modeled by a normal distribution with mean 100 and standard deviation 15.

evablogger [386]

Answer:

4.4% of the population with IQ between 120 and 125.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 100

Standard Deviation, σ = 15

We are given that the distribution of IQ scores is a bell shaped distribution that is a normal distribution.

a) Let X be a person's IQ score.

Then, density functions for IQ scores is given by:

$P(x) = \displaystyle\frac{1}{2\sqrt{2\pi}}e^{-\frac{z^2}{2}}\\\\\text{where,}\\\\z = \frac{x-\mu}{\sigma}\\\\P(x) = \displaystyle\frac{1}{2\sqrt{2\pi}}e^{-\frac{(x-\mu)^2}{2\sigma^2}}\\\\P(x) = \displaystyle\frac{1}{2\sqrt{2\pi}}e^{-\frac{(x-100)^2}{450}}$

b) P(population with IQ between 120 and 125.)

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

$P(120 \leq x \leq 125) = P(\displaystyle\frac{120 - 100}{15} \leq z \leq \displaystyle\frac{125-100}{15}) = P(1.33 \leq z \leq 1.66)\\\\= P(z \leq 1.66) - P(z < 1.33)\\= 0.952 - 0.908 = 0.044 = 4.4\%$

$P(120 \leq x \leq 125) = 4.4\%$

6 0

3 years ago