All categories

3 years ago

A group of hikers walked 2 1/4 km in 3/4 hour. How far will they go if they maintain the same pace for: 2 hours?

Mathematics

2 answers:

USPshnik [31]3 years ago

8 0

3 km because 2 1/4 divided by 3/4 = 3

wariber [46]3 years ago

3 0

Answer: If they maintain the same pace for 2 hours they will go 6 km far.

Step-by-step explanation:

Hi, to solve this problem first we have to calculate the speed rate.

We have to apply the formula ⇒ speed = distance / time

2 1/4 km ÷ 3/4 h = 3 km per hour

Now that we have the rate, we simply have to multiply it by the time they will walk (2 hours) to calculate how far they will go.

2h x 3kmph = 6 km

If they maintain the same pace for 2 hours they will go 6 km far.

You might be interested in

How do i solve log_8(5x+4)=3x-4

Keith_Richards [23]

Answer:

use a calculator

Step-by-step explanation:

3 0

3 years ago

The graph shows the number of hours driven and the number of miles traveled.

Assoli18 [71]

Answer:

x is 4 when y is 180

y is 540 when x is 12

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Write as an improper fraction 7 2/5

Nana76 [90]

Answer:

37/5

Step-by-step explanation:

4 0

3 years ago

) Find the coordinates of the point A' which is the symmetric point

soldier1979 [14.2K]

Let, coordinate of point A' is (x,y).

Since, A' is the symmetric point A(3, 2) with respect to the line 2x + y - 12 = 0.

So, slope of line containing A and A' will be perpendicular to the line 2x + y - 12 = 0 and also their center lies in the line too.

Now, their center is given by :

$C( \dfrac{x+3}{2}, \dfrac{y+2}{2})$

Also, product of slope will be -1 .( Since, they are parallel )

$\dfrac{y-2}{x-3} \times -2 = -1\\\\2y - 4 = x - 3\\\\2y - x = 1$

x = 2y - 1

So, $C( \dfrac{2y -1 +3}{2}, \dfrac{y+2}{2})\\\\C( \dfrac{2y + 2}{2}, \dfrac{y+2}{2})$

Also, C satisfy given line :

$2\times ( \dfrac{2y + 2}{2}) + \dfrac{y+2}{2} = 12\\\\4y + 4 + y + 2 = 24\\\\5y = 18\\\\y = \dfrac{18}{5}$

Also,

$x = 2\times \dfrac{18}{5 } - 1\\\\x = \dfrac{31}{5}$

Therefore, the symmetric points is $A'(\dfrac{31}{5}, \dfrac{18}{5})$ .

7 0

2 years ago

Question 11 12 and 13 Will be brainliest 20 POINTS NO EXPLANATION NEEDED

Mice21 [21]

i read in class 4 but I don't explain the answer

5 0

2 years ago