Answer:
d. $90,000, $60,000, $30,000 respectively.
Explanation:
The computation of price allocated is shown below:-
Ratio of values $90,000 : $60,000 : $30,000
= 3 : 2 : 1
Total cost = $180,000
Equipment = $180,000 × 3 ÷ 6
= $90,000
Installation= $180,000 × 2 ÷ 6
= $60,000
Training = $180,000 × 1 ÷ 6
= $30,000
Therefore the Equipment, Installation, Training is $90,000, $60,000, $30,000 respectively.
Answer:
The correct answer is letter "B": personal ethics.
Explanation:
Personal ethics refers to the moral principle people consider inherent in themselves that drive their behavior. These principles extend to every aspect of their lives and are mainly noticeable in the professional field. Respect, honesty, integrity, and fairness are some examples of personal ethics.
First conflict is a problem and second don't fight with the staff members if you did say sorry from your deeper part of heart to say a big soory
Answer:
A) R(x) = 120x - 0.5x^2
B) P(x) = - 0.75x^2 + 120x - 2500
C) 80
D) 2300
E) 80
Explanation:
Given the following :
Price of suit 'x' :
p = 120 - 0.5x
Cost of producing 'x' suits :
C(x)=2500 + 0.25 x^2
A) calculate total revenue 'R(x)'
Total Revenue = price × total quantity sold, If total quantity sold = 'x'
R(x) = (120 - 0.5x) * x
R(x) = 120x - 0.5x^2
B) Total profit, 'p(x)'
Profit = Total revenue - Cost of production
P(x) = R(x) - C(x)
P(x) = (120x - 0.5x^2) - (2500 + 0.25x^2)
P(x) = 120x - 0.5x^2 - 2500 - 0.25x^2
P(x) = - 0.5x^2 - 0.25x^2 + 120x - 2500
P(x) = - 0.75x^2 + 120x - 2500
C) To maximize profit
Find the marginal profit 'p' (x)'
First derivative of p(x)
d/dx (p(x)) = - 2(0.75)x + 120
P'(x) = - 1.5x + 120
-1.5x + 120 = 0
-1.5x = - 120
x = 120 / 1.5
x = 80
D) maximum profit
P(x) = - 0.75x^2 + 120x - 2500
P(80) = - 0.75(80)^2 + 120(80) - 2500
= -0.75(6400) + 9600 - 2500
= -4800 + 9600 - 2500
= 2300
E) price per suit in other to maximize profit
P = 120 - 0.5x
P = 120 - 0.5(80)
P = 120 - 40
P = $80
Answer:
c. you need a lot of money to buy a home
Explanation:
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