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Cloud [144]
3 years ago
10

In her last game, Mary bowled 199 and this effort raised her average from 177 to 178. To raise her average to 179 with the next

game, what must she bowl?
Mathematics
1 answer:
Mashcka [7]3 years ago
7 0
She must bowl 201 to raise her average
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Factor. 8a2−2ac+12ab−3bc
Masteriza [31]

Answer:

B. (2a +3b)(4a -c)

Step-by-step explanation:

Group the terms pairwise, then factor each pair.

... (8a² -2ac) +(12ab -3bc)

2a is a common factor in the first pair of terms; 3b is a common factor in the second pair of terms. We can factor those out.

... = 2a(4a -c) +3b(4a -c)

Then we see that (4a-c) is a common factor in the result. We can factor that out.

... = (2a +3b)(4a -c) . . . . matches selection B

8 0
3 years ago
Answer correctly and get brainliset
Klio2033 [76]
The answer is the mean is 8. The range is equal to the largest number, 10 minus the smallest number, 5. It equals 5, so d is wrong. The mean is all of the values added together, 80, divided by the number of values, 10. So, 8. The median is the middle which is between 7 and 8, so 7.5. Five has no dots.
6 0
3 years ago
Please help! Thank you
Vanyuwa [196]

Answer:

x = 82°

y = 59°

z = 39°

Step-by-step explanation:

∠x = 1/2(134° + 30°) = 82°

∠z = 180° - 59° - 82° = 39°

arc DF = 2(39°) = 78°

arc DB + arc DF = 134° + 78° = 212°

draw a diameter down from point B to the opposite side of the circle, call that point P:

arc BDP = 180°

(arc BDF) 212° - 180° = 32° (arc PF)

∠PBG = 1/2(32°) = 16°

∠DEB = 1/2(134°) = 67°

∠DBE = 180° - 59° - 67° = 54°

(∠DBE) 54° - (∠z) 39° + (∠PBG) 16° = (∠PBE) 31°

y = 90°- 31° = 59°

5 0
3 years ago
Deshi has 427 marbles and Elaheh has 394 marbles Deshi wants to give 125 marbles to his little brother how many total marbles wi
hjlf

Answer: Deshi will have 302 marbles  and Elaheh will have 519.

Step-by-step explanation:

Deshi's Marbles will subtract 125.

427 - 125 = 302.

Elaheh's Marbles will add 125.

394 + 125= 519.

3 0
2 years ago
Simplify the expression: 2(4 + 6j)
aniked [119]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{8 + 12j}}}}}

Step-by-step explanation:

\sf{2(4 + 6j)}

Distribute 2 through the parentheses

\longrightarrow{ \sf{2 \times 4  + 2 \times 6j}}

\longrightarrow{ \sf{8  + 12j}}

Hope I helped!

Best regards! :D

8 0
3 years ago
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