Answer:
-4 < -13(a+6)-17
-4<-13a+(-78)-17
-4<-13a+(-95)
-4<-13a-95
91<-13a
-91>13a
-7>a
Step-by-step explanation:
Area of the rectangular mat = 12 x 4 = 48 in²
Area of the 3 circles = 3( πr²) = 3(3.14 x 2²) = 37.68 in²
P(landing in a circle) = 37.68/48 = 157/200 = 0.79 (nearest hundredth)
Answer: The probability of landing in one of the circles is 0.79.
Answer:
A sample size of 35 is needed.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find the width W as such

In which
is the standard deviation of the population and n is the size of the sample.
How large must the sample size be if the width of the 95% interval for mu is to be 1.0:
We need to find n for which W = 1.
We have that
, then
. So





Rounding up
A sample size of 35 is needed.
Mmmm c i’m thinking it’s that
Answer:
no
Step-by-step explanation: