Since we know that in π radians there are 180°, thus how many radians in 132°?
Use ac method
for ax²+bx+c=0 when a≠1
multiply a and c, let's call the product r
what 2 numbesr multiply to get r and add to get b
2y²+9y+9=0
2*9=18
wat 2 numbers multiply to get 18 and add to get 9
3 and 6
split it up to that
2y²+3y+6y+9=0
group
(2y²+3y)+(6y+9)=0
factor
y(2y+3)+3(2y+3)=0
undistribute
(y+3)(2y+3)=0
set to zero
y+3=0
y=-3
2y+3=0
2y=-3
y=-3/2
y=-3 and -3/2
it's factored form is (x+3)(2x+3)
<span>Simplifying
fg + -9n = 10j
Solving
fg + -9n = 10j
Solving for variable 'f'.
Move all terms containing f to the left, all other terms to the right.
Add '9n' to each side of the equation.
fg + -9n + 9n = 10j + 9n
Combine like terms: -9n + 9n = 0
fg + 0 = 10j + 9n
fg = 10j + 9n
Divide each side by 'g'.
f = 10g-1j + 9g-1n
Simplifying
f = 10g-1j + 9g-1n</span>
Megan will count more because there are 10 ones in 10, but there are only 4 fives in 20.
