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GREYUIT [131]
3 years ago
8

Fill in the blank: A piecewise function uses different rules for different intervals of the _________.

Mathematics
2 answers:
Margarita [4]3 years ago
7 0
A piecewise function uses different rules for different intervals of the Domain
Bogdan [553]3 years ago
5 0
<span>A piecewise function uses different rules for different intervals of the DOMAIN</span>
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What is the absolute value of 3/4
Minchanka [31]

Answer:

3/4

Step-by-step explanation:

Absolute value is the distance from zero.

3 0
3 years ago
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Find the value of x​
damaskus [11]

Answer:

x=12

Step-by-step explanation:

First, note that the angles shown are vertical angles. In other words, the two equations are equivalent to each other.

Therefore, set the equations equal to each other and solve for x;

6x+7=8x-17

Add 17 to both sides:

6x+24=8x

Subtract 6x from both sides:

24=2x

Divide both sides by 2:

x=12

Therefore, the value of x is 12.

And we're done!

4 0
3 years ago
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Suppose that bugs are present in 1% of all computer programs. A computer de-bugging program detects an actual bug with probabili
lawyer [7]

Answer:

(i) The probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

Step-by-step explanation:

Denote the events as follows:

<em>B</em> = bugs are present in a computer program.

<em>D</em> = a de-bugging program detects the bug.

The information provided is:

P(B) =0.01\\P(D|B)=0.99\\P(D|B^{c})=0.02

(i)

The probability that there is a bug in the program given that the de-bugging program has detected the bug is, P (B | D).

The Bayes' theorem states that the conditional probability of an event <em>E </em>given that another event <em>X</em> has already occurred is:

P(E|X)=\frac{P(X|E)P(E)}{P(X|E)P(E)+P(X|E^{c})P(E^{c})}

Use the Bayes' theorem to compute the value of P (B | D) as follows:

P(B|D)=\frac{P(D|B)P(B)}{P(D|B)P(B)+P(D|B^{c})P(B^{c})}=\frac{(0.99\times 0.01)}{(0.99\times 0.01)+(0.02\times (1-0.01))}=0.3333

Thus, the probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii)

The probability that a bug is actually present given that the de-bugging program claims that bug is present is:

P (B|D) = 0.3333

Now it is provided that two tests are performed on the program A.

Both the test are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is:

P (Bugs are actually present | Detects on both test) = P (B|D) × P (B|D)

                                                                                     =0.3333\times 0.3333\\=0.11108889\\\approx 0.1111

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii)

Now it is provided that three tests are performed on the program A.

All the three tests are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is:

P (Bugs are actually present | Detects on all 3 test)

= P (B|D) × P (B|D) × P (B|D)

=0.3333\times 0.3333\times 0.3333\\=0.037025927037\\\approx 0.037

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

4 0
3 years ago
What is 2÷22 I need help
morpeh [17]
Two divided by twenty-two is .090909 repeating
3 0
3 years ago
Wha is the value of x if the quadrilateral is a kite
Lorico [155]

x+2=13

x=11

Hope this helps :)

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3 years ago
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