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lyudmila [28]
3 years ago
6

To solve the equation for x by completing the square what equation is equivalent to x^2-x-2=0

Mathematics
1 answer:
GuDViN [60]3 years ago
3 0
So to complete the square in
ax^2+bx+c=d form

make sure a=1
subtract c from both sides
take 1/2 of b and square it
add that to both sides
factor perfect square

1x^2-1x-2=0
a=1
move c to other side
add 2 to oth sides
x^2-1x=2
take 1/2 of b and square it
1/2 of -1=-1/2
squaer it
1/4
add that to both sides
x^2-1x+1/4=2+1/4
factor left side
(x-1/2)=2+1/4

first blank is 1/2

2+1/4=8/4+1/4=9/4

blanks are
1/2 and 9/4
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You bought socks for all your friends. Fancy socks cost $15 a pair, and plain socks cost $8 a pair. You have 12 friends, spent e
jonny [76]

Answer:

9 socks for $8

3 socks at $15

Step-by-step explanation:

117 = (15 * x) + (8 * y)

8*9 = 72

15 * 3 = 45

72+ 45 = 117

9 socks at $8

3 socks at $15

4 0
3 years ago
A college student is moving onto campus. The student rents a moving truck for $19.95 plus $0.99 per mile. Before returning the t
Lady bird [3.3K]
What is the cost of renting the truck is driven 190 miles? 406 miles?
C(190) = 22 + 0.1*190 = 22 + 19 = $41
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C(406) = 22 + 0.1*406 = 22+40.6 = $62.60
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6 0
4 years ago
Two dice are tossed together. What is the probability of getting an odd number on the second die and a total of five?
wolverine [178]

Probability = (number of ways to succeed) / (total possible outcomes) .

The total possible results of rolling two dice is

   (6 on the first cube) x (6 on the second one) = 36 possibilities.

How many are successful ?  I need you to clarify something first.
You said that the 'second die' shows an odd number.  When a pair
of dice is rolled, the problem usually doesn't distinguish between them. 
And in fact, you said that they're "tossed together" (like a spinach and
arugula salad ?) so I would understand that they would lose their identity
unless they were, say, painted different colors, and we wouldn't know
which one is the second one.

Oh well, I'll just work it both ways:

First way: 
Two identical dice are tossed.
The total is 5 and ONE cube shows an odd number.

How can that happen ?

1 ... 4
4 ... 1
3 ... 2
2 ... 3         

Four possibilities.  Probability = 4/36 = 1/9 = 11.1% .

=======================================

Second way:
 
A black and a white cube are tossed together.
The total is 5 and the white cube shows an odd number.

How can that happen:

B ... W
4 .... 1
2 .... 3

Only two possibilities.  Probability = 2/36 = 1/18 = 5.6% .

3 0
4 years ago
You have a standard deck of 52 cards. you pick one card and then, with out putting the first card back, you pick a second card.
Diano4ka-milaya [45]


First, find the probability of picking one 9. There are four nines in a deck of 52, so the probability is 4/52, which is 1/13.

The probability of picking a 9 the second time is 1/17, because if a 9 was picked the first time, then there are three 9s left and 51 cards left in total.

To find the probability of both events happening, multiply the individual probabilities together:

(1/13)(1/17)

 The probability that both cards picked will be 9s is 1/221.

6 0
3 years ago
Write the first five terms of the sequence in which the nth term is a_n=(n+1)!/n+1.
VikaD [51]

Answer:a) 1,2,6,24,120

Step-by-step explanation:

The formula for the nth term of the sequence is expressed as

n=(n+1)!/n+1

For the first term, n = 1. Therefore,

(1+1)!/(1+1) = 2!/2 = (2×1)/2 = 1

For the second tern, n = 2. Therefore,

(2+1)!/2+1 = 3! /3 = (3×2×1)/3 = 6/3 = 2

For the third term, n = 3, therefore

(3+1)!/3+1 = 4!/4 =(4×3×2×1)/4 = 6

For the fourth term, n = 4. Therefore

(4+1)!/4+1 = 5!/5 = (5×4×3×2×1)/5 = 24

For the fifth term, n = 5. Therefore

(5+1)!/5+1 = 6!/6 = 6× 5×4×3×2×1)/6 = 120

4 0
3 years ago
Read 2 more answers
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