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3 years ago

Form a polynomial using numbers -4,4,2 with a degree of 3

Mathematics

1 answer:

shtirl [24]3 years ago

3 0

These three roots are sufficient to enable us to form a 3rd degree polynomial:

f(x) = (x+4)(x-4)(x-2) = (x^2 - 16)(x-2) = x^3 - 2x^2 - 16x + 32 (answer)

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Hailey planted

IrinaVladis [17]

Answer:

18 seeds

Step-by-step explanation:

3 x 6 = 18 seeds

3/5 x 30 = 18 seeds

Hope that helps!

7 0

2 years ago

A rectangle measures 2 1/2 inches by 3/4 inches What is its area?

il63 [147K]

Answer:

1 7/8

Step-by-step explanation:

I think you need to times it like 2 1/2 x 3/4, first you make 2 1/2 into 5/2 then times it like this 5/2 x 3/4. the answer is 1 7/8

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2 years ago

Read 2 more answers

Tony buys a CD that is priced at $13.59. He has a coupon for $1.85 off. He pays with a $20 bill. Which is the best whole number

sweet-ann [11.9K]

No he would get back $4.56. Start with $20 -13.59-1.85=4.56

3 0

3 years ago

X+6=x<br> can you help please thank you

Anna35 [415]

x + 6 = x

there is literally no solution.

7 0

3 years ago

Find the coordinates of the image of a triangle with vertices A(0, – 3), B(3, 0), and

lora16 [44]

Answer:

A'(-3,0), B'(0,-3) and C'(4,7)

Step-by-step explanation:

We are given that the vertices of triangle are A(0,-3), B(3,0) and C(-7,4).

We have to find the coordinates of the image of triangle under a rotation of 90° clockwise about the origin.

90° clockwise about the origin

Rule: $(x,y)\rightarrow (y,-x)$

Using the rule

The coordinates of A'

$A(0,-3)\rightarrow A'(-3,0)$

The coordinates of B'

$B(3,0)\rightarrow B'(0,-3)$

The coordinates of C'

$C(-7,4)\rightarrow C'(4,7)$

Hence, the vertices of image of triangle is given by

A'(-3,0), B'(0,-3) and C'(4,7)

8 0

2 years ago