Answer:
6°F
58°F
Step-by-step explanation:
From the data Given :
Temperature rise in Buffalo by noon time = 14°F
The initial temperature at Buffalo = - 8°F
Rise in temperature = 14°F
Therefore, temperature at noon = (-8 + 14)°F = 6°F
B.)
Temperature at 6am in St. Louis = 32°F
Temperature at 6am in Juneau = - 26°F
Temperature difference :
(32 - (-26))°F
32 + 26
= 58°F
Temperature in St. Louis is 58°F higher
Answer:
a. Diego
b. Lin
Step-by-step explanation:
a. Diego
b. Lin
It's pretty easy just do some subtraction.
Actually look and pay attention in class this is like grade 1 math.
Answer:
if i am right it yes yes no
Step-by-step explanation:
Answer: .13
Step-by-step explanation:
63/100=0.63
5/10=0.50
=.13
I took 63 and divided it by 100 to get .63 and took 5 and divided it by 10 to get .50 so I took them and subtracted them to get .13
