What is the expanded form of 337,060 using exponents

1 answer:

7 0

337,060 = (3x10^6) + (3x10^5) + (7x10^4) + (0x10^3) + (0x10^2) + (6x10^1) + (0x10^0)

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Mazyrski [523]

28% of 1.00 = 28
To get your answer, multiply .28 * 100.
28% of $1.00 = 28 cents.

8 0

3 years ago

Sati [7]

What do you need help with?

5 0

3 years ago

tester [92]

Hello!

Here are the steps to your problem:

3x + 5 = x - 3

3x -x = -3 -5

2x = -8

x = -4

I hope this helps you! Have a lovely day!

-Mal

5 0

3 years ago

Gre4nikov [31]

Answer:

Step-by-step explanation:

We khow that the equation of a circle is written this way :

(x-a)²+(y-b)²=r² where (x,y) are the coordinates of the cercle's points and (a,b) the coordinates of the cercle's center and r the radius .

Our task is to khow the values of a and b :

We khow that the center is lying on the line 3x+2y=16⇒ 2y=-3x+16⇒ y= $\frac{-3}{2}$ x+8
We khow that the points P and Q are two points in the cercle
Let Ω be the center of this cercle
we can notice that : PΩ AND QΩ are both equal to the radius ⇒ PΩ=QΩ= r
So let's write the expression of this distance using vectors KHOWING THAT Ω(a,b)
Vector PΩ(a-4,b-6) and Vector QΩ(a-8,b-2)
PΩ= $\sqrt{(a-4)^{2}+(b-6)^{2} }$ and QΩ= $\sqrt{(a-8)^{2}+(b-2)^{2} }$
Let's substitute a by x and b by y
PΩ=QΩ we substitute each distance by its expression
After simplyfying the expressions we get finally : -12+8x-8y=0
now we have -12x +8x-8y=0 and the line equation 3x+2y-16=0
these are simultanious equations so after solving them we get x=3.8 wich is approximatively 4 and y=2
we substitute a by 4 and y by 2 in PΩ to get the radius
we get r = $\sqrt{(4-4)^{2}+(2-6)^{2} }$ = 4
so r²= 16
then the equation is : (x-4)²+(y-2)²=16