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lianna [129]
3 years ago
11

A firm offers routine physical examinations as part of a health service program for its employees. The exams showed that 8% of t

he employees needed corrective shoes, 15% needed major dental work, and 3% needed both corrective shoes and major dental work. What is the probability that an employee selected at random will need either corrective shoes or major dental work?
A. 0.20
B. 0.25
C. 0.50
D. 1.00
Mathematics
1 answer:
Alexxandr [17]3 years ago
6 0

Answer: A. 0.20

Step-by-step explanation:

Let A be the event of employees needed corrective shoes and B be the event that they needed major dental work .

We are given that : P(A)=0.08\ ;\ P(B)=0.15\ ;\ P(A\cap B)=0.03

We know that P(A\cup B)=P(A)+P(B)-P(A\cap B)

Then,   P(A\cup B)=0.08+0.15-0.03= 0.20

Hence, the probability that an employee selected at random will need either corrective shoes or major dental work : P(A\cup B)= 0.20

hence, the correct option is (A).

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Answer:

Step-by-step explanation:

The area of the floor A = Length * Width

Given

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If the length of the floor is 32 m longed than it’s width then;

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200 = (32+W)W

200 = 32W + W²

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Hence the dimension is  5.35ft by 37.35m

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3 years ago
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aivan3 [116]

Answer:

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Step-by-step explanation:

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6 0
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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